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anonymous
 one year ago
Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their axis of symmetry.
f(x), g(x), h(x)
h(x), g(x), f(x)
g(x), h(x), f(x)
h(x), f(x), g(x)
anonymous
 one year ago
Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their axis of symmetry. f(x), g(x), h(x) h(x), g(x), f(x) g(x), h(x), f(x) h(x), f(x), g(x)

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2do you know how to find the axis of symmetry..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not when it is in standard form

karatechopper
 one year ago
Best ResponseYou've already chosen the best response.0You would need to convert to vertex form right? @campbell_st

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nvm b  2a right?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2ok... so if an parabola is in the form \[y = ax^2 + bx + c\] the axis of symmtery is \[x = \frac{b}{2a}\] this may be familar as its part of the general quadratic formula so on the 1st question you have a = 1 and b = 6 so the axis of symmetry is \[x = \frac{6}{2 \times 1}\] just solve it hope that makes sense

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2then repeat the process for the 2nd and 3rd equations.
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