kanwal32
  • kanwal32
if the quadratic equation ax^2+bx+6=0 does not have two distinct real roots, then the least value of 2a+b is
Mathematics
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SOLVED
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chestercat
  • chestercat
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kanwal32
  • kanwal32
@ganeshie8
kanwal32
  • kanwal32
@nincompoop @Luigi0210
kanwal32
  • kanwal32
@dan815

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More answers

kanwal32
  • kanwal32
@UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
what is the discriminant of that quadratic? \[\Delta = b^2-4ac\]
kanwal32
  • kanwal32
b^2-24a<0
UnkleRhaukus
  • UnkleRhaukus
when ∆ > 0 the are two real roots there is only one root when ∆ = 0 is ∆ < 0 there are no real roots
kanwal32
  • kanwal32
yes b^2-4ac<0
kanwal32
  • kanwal32
then
UnkleRhaukus
  • UnkleRhaukus
i think you want \[b^2-24a\leq0\]
kanwal32
  • kanwal32
yes so how to find 2a+b least value
UnkleRhaukus
  • UnkleRhaukus
solve for a (as a function of b)
kanwal32
  • kanwal32
how can we find
UnkleRhaukus
  • UnkleRhaukus
solve the inequality
kanwal32
  • kanwal32
can u solve for this
kanwal32
  • kanwal32
\[-2\sqrt{6}a
kanwal32
  • kanwal32
how???????????
UnkleRhaukus
  • UnkleRhaukus
\[b^2-24a\leq0\\ b^2\leq24a\\ \frac{b^2}{24}\leq a\]
kanwal32
  • kanwal32
then
UnkleRhaukus
  • UnkleRhaukus
2a + b =
UnkleRhaukus
  • UnkleRhaukus
\[2a+b\geq2\cdot\frac{b^2}{12}+b\]
UnkleRhaukus
  • UnkleRhaukus
following?, not following? @kanwal32

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