if the quadratic equation ax^2+bx+6=0 does not have two distinct real roots, then the least value of 2a+b is

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if the quadratic equation ax^2+bx+6=0 does not have two distinct real roots, then the least value of 2a+b is

Mathematics
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Other answers:

what is the discriminant of that quadratic? \[\Delta = b^2-4ac\]
b^2-24a<0
when ∆ > 0 the are two real roots there is only one root when ∆ = 0 is ∆ < 0 there are no real roots
yes b^2-4ac<0
then
i think you want \[b^2-24a\leq0\]
yes so how to find 2a+b least value
solve for a (as a function of b)
how can we find
solve the inequality
can u solve for this
\[-2\sqrt{6}a
how???????????
\[b^2-24a\leq0\\ b^2\leq24a\\ \frac{b^2}{24}\leq a\]
then
2a + b =
\[2a+b\geq2\cdot\frac{b^2}{12}+b\]
following?, not following? @kanwal32

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