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anonymous
 one year ago
Robert bought 2 different candles. the ratio of short candle to the longer candle is 5 : 7. it is known that the longer candle when lighted can melt in 3.5 hours while the shorter candle when lighted can melt in 5 hours. now the two candles are lighted at the same time. after how many hours will the length of two candles be exactly equal ?
anonymous
 one year ago
Robert bought 2 different candles. the ratio of short candle to the longer candle is 5 : 7. it is known that the longer candle when lighted can melt in 3.5 hours while the shorter candle when lighted can melt in 5 hours. now the two candles are lighted at the same time. after how many hours will the length of two candles be exactly equal ?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434959599826:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i sure the shrter one is more fat :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Haha is the answer 2 hours ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im asking this problem, so i dont know the answer. can you show how to get that ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Easy... Let \(5x\) = length of the short candle in meters \(7x\) = length of the longer candle in meters \(t\) = time elapsed in hours after the candles are lit

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3rate of melting of short candle = \(\large \frac{5x ~\text{meters}}{5 \text{hours}} = x\text{ meters/hour}\) starting length of short candle = \(5x\) The length short candle after \(t\) hours is given by \[5xx*t \tag{1}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3rate of melting of long candle = \(\large \frac{7x ~\text{meters}}{3.5 \text{hours}} = 2x\text{ meters/hour}\) starting length of short candle = \(7x\) The length longer candle after \(t\) hours is given by \[7x2x*t \tag{2}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3set both equation equal to each other and solve \(t\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok got it... thanks for your help

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3weird, the time at which the candles get to same heights doesn't depend on their starting lengths

dan815
 one year ago
Best ResponseYou've already chosen the best response.2i dont know why i even change the ratio lol

dan815
 one year ago
Best ResponseYou've already chosen the best response.2which is nice to look at, that the candle is burning exactly 2 times faster
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