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anonymous

  • one year ago

What is the oxidation number for iodine in Mg(IO3)2 ?

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  1. rvc
    • one year ago
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    \[\rm Mg(IO_3)_2\] ?

  2. anonymous
    • one year ago
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    You should be able to firstly place the oxidation numbers of the main ions. For instance, group 1 ions have +1 Group 2 have +2 Hydrogen has +1 Oxygen has -2 For a given compound, you have to make an equation of the oxidation number of all elements present, equating them to zero. Simplifying that equation, we get \[MgI _{2}O _{6}\] For Mg we have 1 atom, for I we have 2 and for O, 6. The equation then becomes\[+2+2x+(-2*6)=0\]

  3. anonymous
    • one year ago
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    \[2x=10\] \[x=5\]

  4. rvc
    • one year ago
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    Good Work :)

  5. anonymous
    • one year ago
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    Nice hearing that, @rvc.

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