## anonymous one year ago What is the oxidation number for iodine in Mg(IO3)2 ?

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1. rvc

$\rm Mg(IO_3)_2$ ?

2. anonymous

You should be able to firstly place the oxidation numbers of the main ions. For instance, group 1 ions have +1 Group 2 have +2 Hydrogen has +1 Oxygen has -2 For a given compound, you have to make an equation of the oxidation number of all elements present, equating them to zero. Simplifying that equation, we get $MgI _{2}O _{6}$ For Mg we have 1 atom, for I we have 2 and for O, 6. The equation then becomes$+2+2x+(-2*6)=0$

3. anonymous

$2x=10$ $x=5$

4. rvc

Good Work :)

5. anonymous

Nice hearing that, @rvc.