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anonymous

  • one year ago

The coordinates of 3 of the vertices of a parallelogram are (–3, 4), (–2, 1), and (2, 6). What is the equation for the line containing the side opposite the side containing the first two vertices? (Remember, opposite sides of a parallelogram are parallel. help !!

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  1. anonymous
    • one year ago
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    I'm guessing x=1... I'm not sure how to solve this problem.

  2. anonymous
    • one year ago
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    me either ..

  3. anonymous
    • one year ago
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    A

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  4. anonymous
    • one year ago
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    B

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  5. anonymous
    • one year ago
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    C

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  6. anonymous
    • one year ago
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    D

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  7. anonymous
    • one year ago
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    Imagine the arrangement is as follows: |dw:1434980951791:dw|

  8. anonymous
    • one year ago
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    mmkay ...

  9. anonymous
    • one year ago
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    |dw:1434981266777:dw| The circled line is the one required, which connects two vertices. Given that they have the same gradient, then the gradient of the circled one is \[\frac{ 4-1 }{ -3-(-2) }=\frac{ 3 }{ -1 }=-3\] This will also be the gradient of the new line that we are looking for. The next, moving onto the required line, to make its equation it is important to choose a point, and it will be the vertex (2,6). Using the original equation, we get \[y-y _{1}=m(x-x _{1})\] Using substitution of the values... \[y-6=-3(x-2)\] \[y=-3x+6+6=-3x+12\]

  10. anonymous
    • one year ago
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    y=3x-12 ? what do i do with that ?

  11. anonymous
    • one year ago
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    That is the answer - the required equation of the line.

  12. anonymous
    • one year ago
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    ooookay. thank you

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