## anonymous one year ago please help and i reward a medal For what value of x is sin x = cos 19°, where 0°< x < 90°? A.38° B.71° C.26° D.19°

1. anonymous

Take note of the following property: $\sin \alpha=\cos 90-\alpha$ or the other way round. So$x=90-19=71$ Answer, B.

2. anonymous

Like it @Hoslos, I'm stealing this solution!