helllllllllllllllp please.. medal and fans A fair coin is tossed 5 times and the number of heads is recorded. (i) The random variable X is the number of heads. State the mean and the variance. (ii) The number of heads is doubled and denoted by the random variable Y. State the mean and variance of Y.

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helllllllllllllllp please.. medal and fans A fair coin is tossed 5 times and the number of heads is recorded. (i) The random variable X is the number of heads. State the mean and the variance. (ii) The number of heads is doubled and denoted by the random variable Y. State the mean and variance of Y.

Mathematics
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|dw:1434986852277:dw| this is first step
yes then... atleast someone to help me..
\[e(x)=\sum_{i=1}^{5}p_ix_i\]

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\[e(x)=\frac{1}{32}*0+\frac{5}{32}*1+\frac{10}{32}*2+\frac{10}{32}*3+\frac{5}{32}*4+\frac{1}{32}*5\]
it is ok , to calculate mean ?
yes thank you so much...
\[var(x)=e[x^2]-e^2[x]\\and\\e[x^2]=\sum_{i=1}^{5}p_ix_i^2\]
can you tell me what;s mean ? then what is the value of var (x) ?
mean is 2.5 var(x)=1.25 right ?
can I see your work ?
\[mean=\frac{80}{32} ?\]
yes its 80/32
yes it is correct
if you want to know more in binomial distribution mean=np=5 (1/2)=2.5 var=n p q =5 (1/2)(1/2)=5/4=1.25

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