## anonymous one year ago Find the rate of change

1. anonymous

2. anonymous

ummm

3. anonymous

let me try

4. anonymous

okk

5. anonymous

6. anonymous

@aloud can you help me out?

7. anonymous

8. anonymous

kind in a tight situation

9. anonymous

i have to go in couple min

10. anonymous

lol ya ik me to

11. anonymous

@H3LPN33DED help plz?

12. anonymous

@TillLindemann

13. anonymous

sorry dianolove idk this one i am only in geometry

14. anonymous

it's okk

15. anonymous

(1,2) (2,3)

16. anonymous

@braydenbunner

17. anonymous

@aloud, that would be an approximation of the rate of change

18. anonymous

however, at the point (2,3) -tangent to curve you would have an exact rate of change

19. anonymous

so the rate of change is (2,3)

20. anonymous

The way to solve this exercise is to first find the equation of the parabola, followed by the derivative of it and for that you will have to choose a particular x - value.

21. anonymous

like (2,1)

22. anonymous

What aboyt the reverse, @Hoslos , if you know the derivative at a point, can you integrate to find original function?

23. anonymous

Let us find the equation of the parabola, using the formula: $y=a(x-p)^{2}+q$, where x,y is from any coordinate of the graph and p and q are the x and y - values of the vertex, respectively. The first attempt is to find a . Replacing values, we get: $1=a(1-3)^{2}+2$ $1=a(-2)^{2}+2$ $1-2=4a$ $a=-0.25$ Next we re-write the equation, by now putting a and the vertex coordinates, giving us: $y=-0.25(x-3)^{2} +2$

24. anonymous

Well, the rate of change will have to end at the derivative, which will mean the change in y with respect to x, @BPDlkeme234 .

25. anonymous

i'm sorry this is just hard

26. anonymous

As for the second part, you differentiate the equation of the formula: $\frac{ d _{y} }{ d _{x} }= -0.5(x-3)$ There it is. Depending on the question, they would tell you a particular value of x runing in the graph. For instance let us say, when the x-value is 2. The rate of change will be $-0.5(2-3)=0.5units/time$ Any question on differentiation, please ask.

27. anonymous

thanks for tryin i still dont get it but thanks