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anonymous
 one year ago
Please help me out. :)
anonymous
 one year ago
Please help me out. :)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0#208 only. :) thankyou.. ^_^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you please type the question so it is easier to see

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oww.. okay.. sure. :) wait a minute..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you see it clear?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep thanks let me find the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thankyou.. :) i'll try to answer it again. ^_^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey there. We will have to use Pythagoras here, part of Mechanics exercises.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahh.. but how to illustrate the several forces?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Relax, I will show you.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For a, you will have diagrammatically, the following representative situation dw:1434984303367:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Finding the hypotenuse will be the resultant force: \[DeltaP=\sqrt{(200)^{2}+100^{2}}=223.7=224N\] For the angle, we can use Sine function, giving us\[\sin \beta=\frac{ 200 }{ 224 }\] \[\beta=\sin^{1} \frac{ 200 }{ 224 }=63.2\] Given that you do not want negative angles, we use the property 90B=9063.2=26.7Degrees. Can you use the same methodology for the other exercises?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434985341630:dw
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