Points A(−1, 2), B(−2, −5) and C(7, −2) are on a circle. What is the area of the circle? Express your answer as a decimal to the nearest tenth.

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Points A(−1, 2), B(−2, −5) and C(7, −2) are on a circle. What is the area of the circle? Express your answer as a decimal to the nearest tenth.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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1. slope of AB 2. mid point of A,B 3. slope of line perpendicular to AB 4. eq. of line (perpendicular bisector) through mid point 5. similarly find the eq. of perpendicular bisector of BC 6. center is point of intersection of perpendicular bisectors (say O) 7.find r=OA 8. area of circle.
\[slope=\frac{ y _{2}-y _{1} }{ x _{2} -x _{1}}\]
mid point\[=\left( \frac{ x _{1} +x _{2}}{ 2 } ,\frac{ y _{1} +y _{2}}{ 2 }\right)\]

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can you help me i dont know what you are talking about can you give me the answer too @surjithayer
first find the slope of AB by the above formula and show me.
\[m=\frac{ -5-2 }{ -2-(-1) }=\frac{ -7 }{ -2+1 }=\frac{ -7 }{ -1 }=7\] slope of line perpendicular to AB=-1/m=-1/7
mid point of A,B
will you show me ?

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