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superhelp101
 one year ago
Which of the following is a possible set of quantum numbers for an electron n, l, m subscript l, m subscript s ?
(1, 1, 0, +one over two )
(2, 1, 1, +one over two )
(3, 2, 3, one over two )
(3, 2, 1, one over two )
superhelp101
 one year ago
Which of the following is a possible set of quantum numbers for an electron n, l, m subscript l, m subscript s ? (1, 1, 0, +one over two ) (2, 1, 1, +one over two ) (3, 2, 3, one over two ) (3, 2, 1, one over two )

This Question is Closed

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1Assuming you know the rules for this, which option do you think is the answer?

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.1I was just confused, haha XD

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1what are you confused about?

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.1i'm not sure how to do it

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1Can you state the rules for quantum numbers?

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.1it's not in my notes :(

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1http://www.kentchemistry.com/links/AtomicStructure/quantumnumbers.htm n, can take on integer values n = 1, 2, 3, ...infinity \(l\), only integer values between 0 and n1 are allowed \(m_l\), only integer values between \(l\) and +\(l\) are allowed \(m_s\), can have values of +1/2 or 1/2

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.1I see.. what would we do next?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1So you need to go through each option individually and see which of these follows the rules.

tywower
 one year ago
Best ResponseYou've already chosen the best response.0HIIIIIIIIIIIIIIIIIIIIIII SUPERHELP101!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.1okay thanks @aaronq :)
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