anonymous
  • anonymous
Please help. I will MEDAL and FAN!!!!! Referring to the figure, on the right triangle shown, find the unknown side length. (If necessary, round to the neartest tenth.)
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1434987008886:dw|
anonymous
  • anonymous
@CallMeKiki @sugarplum15
anonymous
  • anonymous
is that a right angled triangle ?

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anonymous
  • anonymous
No. It doesn't have the box in the corner
anonymous
  • anonymous
its mentioned that its a right angled triangle
anonymous
  • anonymous
use pythagoras
anonymous
  • anonymous
have you been able to do ?
anonymous
  • anonymous
So a^2 would be 8.
anonymous
  • anonymous
And 20 would be c^2?
anonymous
  • anonymous
\[a ^{2} = b ^{2} + c ^{2}\] replace a by 20, b by x and c by 8 \[(20)^{2} = (x)^{2} + (8)^{2}\]
anonymous
  • anonymous
@OM14forever better now ?
anonymous
  • anonymous
how do I find x
anonymous
  • anonymous
20/8=
anonymous
  • anonymous
is that what I should do
anonymous
  • anonymous
\[x ^{2} = 20^{2} - 8^{2}\]
anonymous
  • anonymous
so 12
anonymous
  • anonymous
\[x ^{2}= 400 - 64\] \[x ^{2} = 336\] \[x = \sqrt{336} = 18.3\]
anonymous
  • anonymous
nearest to tenth will be x= 18
anonymous
  • anonymous
ok thanks

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