anonymous one year ago Solve for x: −ax + 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a

1. xapproachesinfinity

$$-ax+3b>5 \Longrightarrow -ax>5-3b \Longrightarrow x<\Large \frac{3b-5}{a}$$

2. xapproachesinfinity

your given option are actually wrong somehow!

3. xapproachesinfinity

unless you miss typed something

4. xapproachesinfinity

oh i see! option D is the same result i got

Find more explanations on OpenStudy