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- Flvs.net

Medal and fan if you help me.

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- Flvs.net

Medal and fan if you help me.

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- Flvs.net

Naomi works in a music shop and earns $42 per day. She earns an extra $2 for each CD she sells. If Naomi wants to earn at least $80 per day, which inequality shows the minimum number of CDs, n, that she should sell?
A. 42 + 2n ≤ 80, so n ≤ 19
B. 42 + 2n ≥ 80, so n ≥ 19
C. 42 + 2n ≥ 80, so n ≥ 36
D. 42 + 2n ≤ 80, so n ≤ 36

- Flvs.net

Can you help?

- Jamierox4ev3r

the key word here is "at least"
which implies that she wants to earn at "the least" $80 per day
So: \(\ge 80\)

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- Jamierox4ev3r

she is already earning 42, so you can just stick that into the equation

- Flvs.net

Then what do I do, I don't understand how to do this kind of math.

- Jamierox4ev3r

it's fine :)
Then, you would use the variable "n" to represent the amount of cd's; the 2 coefficient before "n" represents how much each cd sold earns you ($2).
Therefore, your equation is: 42+2n \(\ge 80\)

- Jamierox4ev3r

then solve the inequality and find out how many cd's that the person must sell in order to earn AT LEAST 80 dollars a day. Try this on your own, but I will guide you along the way if you need

- Flvs.net

So how do I do it?

- Jamierox4ev3r

Solve this like a regular equation.

- Jamierox4ev3r

like so:
42+2n \(\ge 80\)
1.) subtract 42 from both sides:
42+2n \(\ge 80\)
-42 -42
----------
2n \(\ge 80\)
2.) divide 2 from both sides

- Jamierox4ev3r

from here: 2n \(\ge 80\), can you solve for me?

- Jamierox4ev3r

@Flvs.net let me know if you get this. pm me if you have further questions, I can check your work ^_^

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