anonymous
  • anonymous
The function h= is used to model fireworks being launched (or projected) into the air. The function models the height h after x seconds. a) How long will it take the fireworks to reach their greatest height? b) How high will the fireworks be their greatest height?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[h=-16x ^{2}+160x+4\]
xapproachesinfinity
  • xapproachesinfinity
to find the max height you need to take derivative
TrojanPoem
  • TrojanPoem
Find maxima using derivative as xapproaches said then you will get the time put it in the main function and you will get the height.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

xapproachesinfinity
  • xapproachesinfinity
\(\frac{dh}{dx}=-32x+160\) set this equal 0 to find the time it takes to reach maximum
anonymous
  • anonymous
hello mam, i would like to know whether u are used to taking derivatives..?
xapproachesinfinity
  • xapproachesinfinity
you can actually discard calculus and do it with basic tools
xapproachesinfinity
  • xapproachesinfinity
that's just a parabola! and you learned that the prabolas has max at \(\left (\frac{-b}{2a}, h(\frac{-b}{2a})\right )\)
xapproachesinfinity
  • xapproachesinfinity
when a<0 that is
xapproachesinfinity
  • xapproachesinfinity
a being the leading coefficient!

Looking for something else?

Not the answer you are looking for? Search for more explanations.