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anonymous

  • one year ago

n ΔABC, BC = a = 16, AC = b = 10, and m∠C = 22°. Which equation can you use to find the value of c = AB?

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  1. Baseballguy101
    • one year ago
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    can i see the answer choices?

  2. anonymous
    • one year ago
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    there are none, you have to type your answer

  3. anonymous
    • one year ago
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    here is the picture! http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/f0e6b9bb6f804e60999f40d25bb55b7c

  4. Michele_Laino
    • one year ago
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    here you can apply the theorem of Carnot, namely: \[\Large \begin{gathered} {c^2} = {a^2} + {b^2} - 2ab\cos \left( {22} \right) = \hfill \\ \hfill \\ = {16^2} + {10^2} - 2 \times 16 \times 10\cos \left( {22} \right) = ... \hfill \\ \end{gathered} \]

  5. anonymous
    • one year ago
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    i dont get it?

  6. Michele_Laino
    • one year ago
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    ok! Now you have to compute this: \[\Large \sqrt {59.30} = ...?\]

  7. Michele_Laino
    • one year ago
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    what do you get?

  8. anonymous
    • one year ago
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    none of it, i've been working on this for 3 days (not this particular question) and it only gets more and more confusing

  9. Michele_Laino
    • one year ago
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    we have: \[\large \begin{gathered} {c^2} = {a^2} + {b^2} - 2ab\cos \left( {22} \right) = \hfill \\ \hfill \\ = {16^2} + {10^2} - 2 \times 16 \times 10\cos \left( {22} \right) = \sqrt {59.30} \cong 7.7 \hfill \\ \end{gathered} \]

  10. Michele_Laino
    • one year ago
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    am I right?

  11. anonymous
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    to see it written out, makes it somewhat easier but when its a different problem and i try and do it myself, i get it wrong

  13. Michele_Laino
    • one year ago
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    that is a simple application of the Theorem of Carnot

  14. anonymous
    • one year ago
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    thank you

  15. Michele_Laino
    • one year ago
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    :)

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