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anonymous
 one year ago
Can someone please help me with this?
A dirt bike racer wants to plan a path between a giant boulder and a fence that lines his property. Using these as the focus and directrix, how can the racer plan a parabolic path that will be equidistant from the boulder and the fence at all times? Describe your method in full sentences.
anonymous
 one year ago
Can someone please help me with this? A dirt bike racer wants to plan a path between a giant boulder and a fence that lines his property. Using these as the focus and directrix, how can the racer plan a parabolic path that will be equidistant from the boulder and the fence at all times? Describe your method in full sentences.

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misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0By using distance formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, what did you just do?

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0I plugged in distance formula

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0the biker wants to go tthrough the same distance as the boulder & fence.

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0Let's work it out; what do you think it is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If he knew the vertex, he can find the value of p (the distance from the vertex to the focus). that's all I know @misssunshinexxoxo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2 = 4py, his equation

True_Alpha_Wolf
 one year ago
Best ResponseYou've already chosen the best response.0im bad at math
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