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- anonymous

Can someone please help me with this?
A dirt bike racer wants to plan a path between a giant boulder and a fence that lines his property. Using these as the focus and directrix, how can the racer plan a parabolic path that will be equidistant from the boulder and the fence at all times? Describe your method in full sentences.

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Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
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- anonymous

- jamiebookeater

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- misssunshinexxoxo

By using distance formula

- anonymous

wait, what did you just do?

- misssunshinexxoxo

I plugged in distance formula

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- misssunshinexxoxo

the biker wants to go tthrough the same distance as the boulder & fence.

- anonymous

I'm very confused

- misssunshinexxoxo

Let's work it out; what do you think it is?

- anonymous

If he knew the vertex, he can find the value of p (the distance from the vertex to the focus). that's all I know @misssunshinexxoxo

- anonymous

x^2 = 4py, his equation

- True_Alpha_Wolf

im bad at math

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