PLEAE HELP I GIVE ANYTHING Using the completing-the-square method, find the vertex of the function f(x) = 5x2 + 10x + 8 and indicate whether it is a minimum or a maximum and at what point. Maximum at (1, 8) Minimum at (1, 8) Maximum at (–1, 3) Minimum at (–1, 3)

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PLEAE HELP I GIVE ANYTHING Using the completing-the-square method, find the vertex of the function f(x) = 5x2 + 10x + 8 and indicate whether it is a minimum or a maximum and at what point. Maximum at (1, 8) Minimum at (1, 8) Maximum at (–1, 3) Minimum at (–1, 3)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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help please
\(\large\color{black}{ \displaystyle f(x)=5x^2+10x+8 }\) factor the 1st 2 terms out of 5, \(\large\color{black}{ \displaystyle f(x)=5(x^2+2x)+8 }\) then, tell me what number would you want added into the parenthesis ?

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Other answers:

1
b/2squared right?
yes, 1 is the number you need added. And now I will use a technique to which I refer to as a magic zero.
\(\large\color{black}{ \displaystyle f(x)=5(x^2+2x)+8 }\) \(\large\color{black}{ \displaystyle f(x)=5(x^2+2x\color{blue}{+1}\color{red}{-1})+8 }\)
then, take the negative one (which I labelled in red) out of the parenthesis, by expanding.
\(\large\color{black}{ \displaystyle f(x)=5(x^2+2x\color{blue}{+1}\color{red}{-1})+8 }\) \(\large\color{black}{ \displaystyle f(x)=5(x^2+2x\color{blue}{+1})+5(\color{red}{-1})+8 }\) \(\large\color{black}{ \displaystyle f(x)=5(x^2+2x\color{blue}{+1})-5+8 }\) \(\large\color{black}{ \displaystyle f(x)=5(x^2+2x\color{blue}{+1})+3 }\)
Now, you need to do the very last step
5(x+1)^2+3?
answer choice D?
yes

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