lizz123
  • lizz123
Medal One cell phone plan charges 20 dollars per month plus 0.15 cents per minute used. A second cell phone plan charges 35 dollars per month plus 0.10 cents per minute used. Find the number of minutes you must talk to have the same cost for both calling plans.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Michele_Laino
  • Michele_Laino
the cost for the first phone is: \[{c_1} = 20 + 0.15 \times m\] where m is the number of minutes. Whereas the cost for the second phone is: \[{c_2} = 35 + 0.10 \times m\]
Michele_Laino
  • Michele_Laino
now we have to know the number m of minute
Michele_Laino
  • Michele_Laino
minutes*

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More answers

lizz123
  • lizz123
\[c _{1}=20+.15\times1\] 20.15
lizz123
  • lizz123
c1=20+.15*2 20.30
Michele_Laino
  • Michele_Laino
yes! nevertheless we have to find the value of m. In order to that we see that the cost c_1 is equal to the cost c_2 when the subsequent equation holds: \[\begin{gathered} {c_1} = {c_2} \hfill \\ 20 + 0.15 \times m = 35 + 0.10 \times m \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
please solve that equation for m
lizz123
  • lizz123
Can I do a chart
Michele_Laino
  • Michele_Laino
if you want you can do a chart. We can get the answer if we solve that equation for m
Michele_Laino
  • Michele_Laino
\[\Large 20 + 0.15 \times m = 35 + 0.10 \times m\]
lizz123
  • lizz123
C1=20+0.15*3= 20.45 C2=20+0.10*3= 20.330
lizz123
  • lizz123
I mean 20.30
lizz123
  • lizz123
So I have to find the same answer for the same time of minutes
Michele_Laino
  • Michele_Laino
ok! Please substitute m=100, what do you get?
lizz123
  • lizz123
\[\huge c _{1}=20+.15 * 100 = 35\]
Michele_Laino
  • Michele_Laino
and c_2?
lizz123
  • lizz123
\[\huge c _{2}= 35 +.10 * 100=45\]
Michele_Laino
  • Michele_Laino
ok! So they are different again. I think that the solution is m=300. Am I right?
lizz123
  • lizz123
\[\huge c _{1}= 20 + .15*300= 65\] \[\huge c _{2}=35+.10*300=65\] Yes, m does equal 300.
Michele_Laino
  • Michele_Laino
perfect! So you can do your chart, using the subsequent values for m: 1, 20, 50, 100, 300 for example
lizz123
  • lizz123
okay thanks
Michele_Laino
  • Michele_Laino
:)

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