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HelloKitty17
 one year ago
FAN AND MEADAL!!!!!!!!!!!!!!!!!!!!
HelloKitty17
 one year ago
FAN AND MEADAL!!!!!!!!!!!!!!!!!!!!

This Question is Closed

HelloKitty17
 one year ago
Best ResponseYou've already chosen the best response.0Part A: Divide (8x4y3 + 4x3y2  2x2y  12x2y4) by 2x2y. Show your work, and justify each step. (6 points) Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points) Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0What do you think the answer is?

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0On OS; we need to make sure you understand the work,

HelloKitty17
 one year ago
Best ResponseYou've already chosen the best response.0I don't how how do divide it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought I already showed you how to do this one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Please don't give out direct answers :) @ Asker  Instead, try engaging with the helper so you can learn better and understand where their answer is coming from. As the saying goes… \(\\\color{darkblue}{Give~a~man~a~fish,~he~eats~for~a~day.}\) \(\\\color{pink}{Teach~a~man~to~fish,~he~eats~for~a~lifetime.}\)

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0@OregonDuck previously accused me of plagiarism and keeps on excessive tagging

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is a test Q. We do not help on tests.

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0Yes very true @Aureyliant

HelloKitty17
 one year ago
Best ResponseYou've already chosen the best response.0YOU KNOW WHAT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0This is a spammer playing around

HelloKitty17
 one year ago
Best ResponseYou've already chosen the best response.0GET LOST EVERYONE

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually, I tried to thoroughly help you through the entire thing and you got an attitude because I didn't just give you the answer.

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0Please call a moderator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @karatechopper @perl

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0wow this is supid this is not even a test

HelloKitty17
 one year ago
Best ResponseYou've already chosen the best response.0LEAVE EVERYONE NOW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0who are you going to call now the police?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why am i involved in this lol?

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0@megan_tanuis don't take them personally; they did this to me also.

karatechopper
 one year ago
Best ResponseYou've already chosen the best response.0Wow chill. All of you. You all know Be Nice is a part of the CoC, now apply it. Second, HelloKitty17, it is correct that we do not help on tests because quite obviously that is considered cheating. If someone helped you before, you should have probably taken it without getting irritated with them. Also, they can chill on your question, but throwing a tantrum won't make them leave, in all humble respect. Now, if you have an issue then please report. The mods will look into it. Good day everyone, happy helping, asking, exploring. Ciao. KC
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