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anonymous
 one year ago
I've searched the internet with no success. Please help.
If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(2)g(1)]^2
anonymous
 one year ago
I've searched the internet with no success. Please help. If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(2)g(1)]^2

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2first find f(2)  plug in 2 for x into the x^2+1

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2then find g(1)  plug in 1 for x into the 3x+1

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2tell me what you get for f(2) and g(1) (respectively) please...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So f(2) would plug in and make it 2^2 +1 = 5 and g(1) would plug in to make it 3(1) + 1 = 4, but how would the power at the end work?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2f(2)=5 g(1)=4 so then [ f(2)g(1) ] ^2 becomes [5  4]^2

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2and that is equal t☼ ?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2you are first subtracting f(2)g(1) (that is subtract 54) AND only then take the second power

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2(AB)^2 is not same as A^2B^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So then you would have 1^2?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2and that is same as ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Thanks for catching me there.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2sure, not a problem!

phi
 one year ago
Best ResponseYou've already chosen the best response.0to do the arithmetic correctly, remember *order of operations* people learn various mnemonics PEDMAS for example, which means you do the first on the list before moving on to the next: parens, exponents, divide/multiply, add/subtract thus with (54)^2 you do the stuff inside the parens before doing the exponents 1^2 now you can do the exponent: 1*1 = 1
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