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anonymous

  • one year ago

I've searched the internet with no success. Please help. If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)]^2

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  1. SolomonZelman
    • one year ago
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    first find f(2) - plug in 2 for x into the x^2+1

  2. SolomonZelman
    • one year ago
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    then find g(1) - plug in 1 for x into the 3x+1

  3. SolomonZelman
    • one year ago
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    tell me what you get for f(2) and g(1) (respectively) please...

  4. anonymous
    • one year ago
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    So f(2) would plug in and make it 2^2 +1 = 5 and g(1) would plug in to make it 3(1) + 1 = 4, but how would the power at the end work?

  5. SolomonZelman
    • one year ago
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    f(2)=5 g(1)=4 so then [ f(2)-g(1) ] ^2 becomes [5 - 4]^2

  6. SolomonZelman
    • one year ago
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    and that is equal t☼ ?

  7. anonymous
    • one year ago
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    25 - 16 = 9

  8. anonymous
    • one year ago
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    Thanks a thousand!

  9. SolomonZelman
    • one year ago
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    no no

  10. SolomonZelman
    • one year ago
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    you are first subtracting f(2)-g(1) (that is subtract 5-4) AND only then take the second power

  11. SolomonZelman
    • one year ago
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    (A-B)^2 is not same as A^2-B^2

  12. anonymous
    • one year ago
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    So then you would have 1^2?

  13. SolomonZelman
    • one year ago
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    yes

  14. SolomonZelman
    • one year ago
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    and that is same as ?

  15. anonymous
    • one year ago
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    One.

  16. SolomonZelman
    • one year ago
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    yup

  17. anonymous
    • one year ago
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    Okay. Thanks for catching me there.

  18. SolomonZelman
    • one year ago
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    sure, not a problem!

  19. phi
    • one year ago
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    to do the arithmetic correctly, remember *order of operations* people learn various mnemonics PEDMAS for example, which means you do the first on the list before moving on to the next: parens, exponents, divide/multiply, add/subtract thus with (5-4)^2 you do the stuff inside the parens before doing the exponents 1^2 now you can do the exponent: 1*1 = 1

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