anonymous
  • anonymous
I've searched the internet with no success. Please help. If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)]^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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SolomonZelman
  • SolomonZelman
first find f(2) - plug in 2 for x into the x^2+1
SolomonZelman
  • SolomonZelman
then find g(1) - plug in 1 for x into the 3x+1
SolomonZelman
  • SolomonZelman
tell me what you get for f(2) and g(1) (respectively) please...

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anonymous
  • anonymous
So f(2) would plug in and make it 2^2 +1 = 5 and g(1) would plug in to make it 3(1) + 1 = 4, but how would the power at the end work?
SolomonZelman
  • SolomonZelman
f(2)=5 g(1)=4 so then [ f(2)-g(1) ] ^2 becomes [5 - 4]^2
SolomonZelman
  • SolomonZelman
and that is equal t☼ ?
anonymous
  • anonymous
25 - 16 = 9
anonymous
  • anonymous
Thanks a thousand!
SolomonZelman
  • SolomonZelman
no no
SolomonZelman
  • SolomonZelman
you are first subtracting f(2)-g(1) (that is subtract 5-4) AND only then take the second power
SolomonZelman
  • SolomonZelman
(A-B)^2 is not same as A^2-B^2
anonymous
  • anonymous
So then you would have 1^2?
SolomonZelman
  • SolomonZelman
yes
SolomonZelman
  • SolomonZelman
and that is same as ?
anonymous
  • anonymous
One.
SolomonZelman
  • SolomonZelman
yup
anonymous
  • anonymous
Okay. Thanks for catching me there.
SolomonZelman
  • SolomonZelman
sure, not a problem!
phi
  • phi
to do the arithmetic correctly, remember *order of operations* people learn various mnemonics PEDMAS for example, which means you do the first on the list before moving on to the next: parens, exponents, divide/multiply, add/subtract thus with (5-4)^2 you do the stuff inside the parens before doing the exponents 1^2 now you can do the exponent: 1*1 = 1

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