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unicwaan
 one year ago
Can someone help me verify the identity?
sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x
unicwaan
 one year ago
Can someone help me verify the identity? sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x

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BTaylor
 one year ago
Best ResponseYou've already chosen the best response.1so, this? \[\frac{\sin x}{1\cos{x}} + \frac{\sin x}{1\cos{x}} = 2\csc x\]

unicwaan
 one year ago
Best ResponseYou've already chosen the best response.0yes except the it's 1 cos and 1 + cos sorry

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0first convert the 2 fractions on left side to one fraction

BTaylor
 one year ago
Best ResponseYou've already chosen the best response.1You want to use the identity \(1\cos^2 x = \sin^2 x\). Multiply the 1  cos x by (1 + cos x) on top and bottom, and you will have sin^2 x on the bottom.

unicwaan
 one year ago
Best ResponseYou've already chosen the best response.0Okay I understand that step BTaylpr but I don't know how the make the other fraction the same like what welshfella wants me to do

BTaylor
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sin x}{1\cos{x}} \cdot \frac{1+\cos x}{1+\cos x} + \frac{\sin x}{1+\cos{x}} \cdot \frac{1\cos x}{1\cos x} = 2\csc x\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you can also just add, you will get it that way too

unicwaan
 one year ago
Best ResponseYou've already chosen the best response.0Oh the conjugate! I forgot about that!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{b}{1+a}+\frac{b}{1a}=\frac{b(1a)+b(1+a)}{(1a)(1+a)}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you get \[\frac{2b}{1a^2}\]

unicwaan
 one year ago
Best ResponseYou've already chosen the best response.0Thank you I justed needed that step to get me started, I can figure the rest out :)
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