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anonymous

  • one year ago

How would you complete the square on the left side of this equation? x^2-6x=15 A. Add 6 to both sides of the equation. B. Subtract 6 from both sides of the equation. C. Add 9 to both sides of the equation. D. Subtract 9 from both sides of the equation.

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  1. welshfella
    • one year ago
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    you need to convert the left side to (x - 3)^2 if you expand that you'll find that the last number is what you want

  2. misty1212
    • one year ago
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    HI!!

  3. misty1212
    • one year ago
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    two steps only what is half of 6?

  4. anonymous
    • one year ago
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    3

  5. misty1212
    • one year ago
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    right and what is \(3^2\)

  6. anonymous
    • one year ago
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    9

  7. misty1212
    • one year ago
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    that is your answer , 9

  8. anonymous
    • one year ago
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    D

  9. misty1212
    • one year ago
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    because if \[x^2-6x=15\] then adding 9 gives \[x^2-6x+9=15+9\\ (x-3)^2=24\]\]

  10. misty1212
    • one year ago
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    no dear never subtract when you are completing the square you always ADD

  11. anonymous
    • one year ago
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    Thanks (;

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