anonymous
  • anonymous
How would you complete the square on the left side of this equation? x^2-6x=15 A. Add 6 to both sides of the equation. B. Subtract 6 from both sides of the equation. C. Add 9 to both sides of the equation. D. Subtract 9 from both sides of the equation.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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welshfella
  • welshfella
you need to convert the left side to (x - 3)^2 if you expand that you'll find that the last number is what you want
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
two steps only what is half of 6?

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anonymous
  • anonymous
3
misty1212
  • misty1212
right and what is \(3^2\)
anonymous
  • anonymous
9
misty1212
  • misty1212
that is your answer , 9
anonymous
  • anonymous
D
misty1212
  • misty1212
because if \[x^2-6x=15\] then adding 9 gives \[x^2-6x+9=15+9\\ (x-3)^2=24\]\]
misty1212
  • misty1212
no dear never subtract when you are completing the square you always ADD
anonymous
  • anonymous
Thanks (;

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