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Fraction or Factoring?

x-2 / 3x-9 divided by x^2 + x - 6 / x^2-4x+3

This is the question, Fraction division I suppose.

are u looking for x

It just says simplify your answer as much as possible

I think you mean this, correct?
\(\dfrac{x - 2}{3x - 9} \div \dfrac{x^2 + x - 6}{x^2-4x+3} \)

yes mathstudent55 that's exactly how the problem looks

You are dividing fractions.
How do you divide a fraction by a fraction?

this is a question on the pretest packet

yes.

Okay I'm with you so far.

Right that makes sense. So x-3 and x+3 would cancel out.

No.
Factors have to be exactly the same to cancel out.

Oh..

Okay.. so from there how can I simplify further?

That is the final answer.

okay thank you very much!

You're welcome.