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anonymous

  • one year ago

f(0) = -5 f(1) = 20 f(n) = -4•f(n-1) - 3•f(n-2); for n > 1

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  1. anonymous
    • one year ago
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    can anyone help me figure out how to work this I got the right answer but I don't remember how I did it

  2. xapproachesinfinity
    • one year ago
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    what are you looking for here?

  3. anonymous
    • one year ago
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    just how to solve the equation again the sequence is -5, 20, -65, 200, ... Just don't remember how i figured it out

  4. xapproachesinfinity
    • one year ago
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    let me rewrite your problem \(f(0)=-5~~and ~~f(1)=20\) the recursive formula is given by \(f(n)=-4f(n-1)-3f(n-2)) ~~~for ~~n>1\)

  5. xapproachesinfinity
    • one year ago
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    so the first two term of this sequence are -5,20 and you said you are looking for how many terms?

  6. xapproachesinfinity
    • one year ago
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    is that your concern?

  7. anonymous
    • one year ago
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    I just can't seem to get the same sequence again

  8. xapproachesinfinity
    • one year ago
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    to find the next term you just use that recursive formula f(2)=-4f(1)-3f(0)=-4(20)-3(-5)=-80+15=-65

  9. anonymous
    • one year ago
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    I remember now thank you so much for your help

  10. xapproachesinfinity
    • one year ago
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    so for f(3)=-4f(2)-3f(1)=-4(-65)-3(20)=....?

  11. xapproachesinfinity
    • one year ago
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    No problem!

  12. anonymous
    • one year ago
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    it makes more sense than what I was doing

  13. xapproachesinfinity
    • one year ago
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    what were you doing?

  14. anonymous
    • one year ago
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    i was trying to plug in the numbers to figure out for 2 and using the solutions like n - (-5)

  15. xapproachesinfinity
    • one year ago
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    hmm you went off the hock lol

  16. xapproachesinfinity
    • one year ago
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    well you got it now :)

  17. anonymous
    • one year ago
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    again thank you so much

  18. xapproachesinfinity
    • one year ago
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    no problem :)

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