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MyDilemma
 one year ago
Can someone help me understand this?
"the midpoint of uv is (5, 11). The coordinates of one endpoint are U(3, 5) find the coordinates of endpoint v"
MyDilemma
 one year ago
Can someone help me understand this? "the midpoint of uv is (5, 11). The coordinates of one endpoint are U(3, 5) find the coordinates of endpoint v"

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misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.1y=mx+b y=ΔyΔxx+b y=y2−y1x2−x1x+b y=(−11)−55−3x+b y=−162x+b y=−8x+b substitute in a point to figure out b (I'll put U in). 5=(−8)(3)+b 5=−24+b b=29 So the equation of you're line is: y=−8x+29 Now the symmetry part: The midpoint is +2 in the x direction, so add another 2 to the midpoint to get V's x coordinate. y3=−8x3+29 y3=−8(7)+29 y3=−56+29 y3=−27 V should be (7, 27) s=(Δy)2+(Δx)2−−−−−−−−−−−−√ s=(y2−y1)2+(x2−x1)2−−−−−−−−−−−−−−−−−−√ s=(−11−5)2+(5−3)2−−−−−−−−−−−−−−−−−√ s=(−16)2+(2)2−−−−−−−−−−−√ s=256+4−−−−−−√ s=260−−−√ midpoint to V s=(Δy)2+(Δx)2−−−−−−−−−−−−√ s=(y3−y2)2+(x3−x2)2−−−−−−−−−−−−−−−−−−√ s=((−27)−(−11))2+(7−5)2−−−−−−−−−−−−−−−−−−−−−−√ s=(−16)2+(2)2−−−−−−−−−−−√ s=256+4−−−−−−√ s=260−−−√

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.1If you have any questions here to help!

MyDilemma
 one year ago
Best ResponseYou've already chosen the best response.0Okay thank you so much!(:

MrNood
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435010934140:dw WOW That seems a complicated explanation for a simple concept The midpoint is middle of UV in both X and Y direction SO Find how far to move from end poit to midpoint in x then add the same amount again Find out how far to move from endpoint ot midpoint in Y then add the same amount again. (Note value to 'add' may be negative)

MyDilemma
 one year ago
Best ResponseYou've already chosen the best response.0@missunshinexxoxo can you help me with one more?

MyDilemma
 one year ago
Best ResponseYou've already chosen the best response.0Find the distance between points m(6, 16) and z(1, 14) to the nearest tenth
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