## anonymous one year ago Can someone help me with this problem. A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?

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1. anonymous

When you have coordinates, use the formula of Pythagoras to find the lengths:$l=\sqrt{(y _{1}-y)^{2}+(x _{1}-x)^{2}}$ |dw:1435053334718:dw| No we find the lengths AB, AC and BC.

2. anonymous

When you have coordinates, use the formula of Pythagoras to find the lengths:$l=\sqrt{(y _{1}-y)^{2}+(x _{1}-x)^{2}}$ |dw:1435053334718:dw| No we find the lengths AB, AC and BC.

3. anonymous

Given coordinates, to find the lengths, we will have to use Pythagoras theorem:$l=\sqrt{(y-y _{1})^{2}+(x-x _{1})^{2}}$ |dw:1435056128195:dw|

4. anonymous

$AC=\sqrt{(8-0)^{2}+(0-6)^{2}}=10$ $AB=\sqrt{(0-0)^{2}+(0-6)^{2}}=6$$BC=\sqrt{(8-0)^{2}+(0-0)^{2}}=8$ $P=s_{1}+s _{2}+s _{3}=6+8+10=24units$