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vera_ewing

  • one year ago

Amy is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd}, and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∪ B.

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  1. mathmate
    • one year ago
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    The possible sums of two number cubes \(\in \Omega =\{{2,3,4,5....11,12}\}\) A={3,5,7,9,11} ..... odd sum B={3,6,9,12}...... outcome divisible by 3 So what is A\(\cup\)B ? See following link for an explanation of set operators. http://www.mathsisfun.com/sets/venn-diagrams.html

  2. vera_ewing
    • one year ago
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    Ohhh so this {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} is not the answer?

  3. mathmate
    • one year ago
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    1 is not a possible outcome if we are looking for the sum of the number cubes. See my previous post for help.

  4. mathmate
    • one year ago
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    No, this is the set of possible sums when we throw two number cubes! There are conditions to A and B, and you need to find \(A\cup B\).

  5. vera_ewing
    • one year ago
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    Oh then it would be {3, 5, 6, 7, 9, 11, 12} right?

  6. mathmate
    • one year ago
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    Yes, {3, 5, 6, 7, 9, 11, 12} is A \(\cup\) B

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