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vera_ewing
 one year ago
Amy is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd}, and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∪ B.
vera_ewing
 one year ago
Amy is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd}, and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∪ B.

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mathmate
 one year ago
Best ResponseYou've already chosen the best response.1The possible sums of two number cubes \(\in \Omega =\{{2,3,4,5....11,12}\}\) A={3,5,7,9,11} ..... odd sum B={3,6,9,12}...... outcome divisible by 3 So what is A\(\cup\)B ? See following link for an explanation of set operators. http://www.mathsisfun.com/sets/venndiagrams.html

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh so this {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} is not the answer?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.11 is not a possible outcome if we are looking for the sum of the number cubes. See my previous post for help.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1No, this is the set of possible sums when we throw two number cubes! There are conditions to A and B, and you need to find \(A\cup B\).

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Oh then it would be {3, 5, 6, 7, 9, 11, 12} right?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Yes, {3, 5, 6, 7, 9, 11, 12} is A \(\cup\) B
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