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anonymous
 one year ago
find the xintercepts of the parabola with vertex (4,1) and yintercept (0,15) write your answer in this form:(x1,y1),(x2,y2) f necessary, round to the nearest Hundredth
anonymous
 one year ago
find the xintercepts of the parabola with vertex (4,1) and yintercept (0,15) write your answer in this form:(x1,y1),(x2,y2) f necessary, round to the nearest Hundredth

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well the vertex form of a parabola is \[y=a(x  h)^2 + k\] where (h, k) is the vertex. so substitute you vertex values, h = 4 and k = 1 into the equation. tThe yintercept is on the parabola... so to find the value of a you need to substitute x = 0 and y = 15 and solve for a. then you can rewrite the equation of the parabola in standard form that's the 1st part hope it makes sense

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0once you have the equation in standard form you may need to use the general quadratic formula for the x intercepts

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0soo would it be y=x^28x+15

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0that's the correct equation... and the equation can be factored.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so what did you get for the xintercepts

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0the equation is \[y=x^2  8x + 15~~~~then~~~~y=(x 5)(x3)\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so the intercepts are

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0where y = 0 so solve x  5 = 0 and x  3 = 0

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ok.... so the xintercepts these are points on the xaxis so y = 0 if you have a parabola to find the xintercepts let y = 0 and solve for x so \[0 = x^2  8x + 15~~~or~~~0 =(x 5)(x 3)\] if either of the factors (x 5) or (x 3) are equal to zero the equation is equal to zero... so then you need to let the factors equal zero and solve for x so solve x  5 = 0 and x  3 = 0 what would you have...?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0the other thing to think about is that the xintercepts are the same distance from the x value in the vertex .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0am go fail this test

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so if you the solve the 2 equations what do you get x  5 = 0 and x  3 = 0

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0these values are the xintercepts

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0correct so the intercepts are at (3,0) and (5, 0) the vertex has an x value of x = 4... the intercepts are the same distance from this value

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so did you write the intercepts as (3, 0) and (5, 0)..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0here is a graph of the parabola you gave... and it meets all the conditions... can you check the vertex is (4, 1) and yintercept is y = 15 or (0. 15)
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