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soo would it be y=x^2-8x+15

that's the correct equation...
and the equation can be factored.

its wrong

so what did you get for the x-intercepts

-4

the equation is
\[y=x^2 - 8x + 15~~~~then~~~~y=(x -5)(x-3)\]

so the intercepts are

where y = 0
so solve
x - 5 = 0 and x - 3 = 0

am confused

am go fail this test

so if you the solve the 2 equations what do you get
x - 5 = 0 and x - 3 = 0

these values are the x-intercepts

x=5,3

thank u soo much

yw

it was wrong

so did you write the intercepts as (3, 0) and (5, 0)..?

yea

here is a graph of the parabola you gave... and it meets all the conditions...
can you check the vertex is (4, -1) and y-intercept is y = 15 or (0. 15)