In right ∆LMN, sin M = 0.759. What is cos N? 0.121 0.241 0.349 0.651 0.759

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In right ∆LMN, sin M = 0.759. What is cos N? 0.121 0.241 0.349 0.651 0.759

Mathematics
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\[\sin ^2 x+ \cos ^2 x =1\]

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M + N = 90, N = 90 -M cos N = cos (90 -M) =cos 90 cos M + sin 90 sin M cos 90 =0 and sin 90 =1 cos N = sin M
idk what any of that means aha im sorry i had a horrible teacher :(
Answer would be E
No worries let's work it out
Can't be true. If the sin = cos, the angles would both be 45 and sin and cos would be .707
\[(.759)^2+\cos ^2N=1\] \[\cos ^2N=1-.576=.423919\] \[\cos N=\sqrt{.423919}=.651\]

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