MEDAL!! ALGEBRA 2 19. l-4b-8l+l-1-b^2l +2b^3;b=2

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

MEDAL!! ALGEBRA 2 19. l-4b-8l+l-1-b^2l +2b^3;b=2

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\left| -4(2) - 8 \right| + \left| -1-(2)^2 \right| + 2(2)^3 \]
You are basically solving the above ^ Since they've told you that " b = 2" , this means that you just sub (plug) in 2 where the "b" is. Basically REPLACE all the "b's" with 2 and solve :) BUT you want to take note of the absolute value sign also...
So firstly, let's simplify the parts inside the first absolute sign " -4(2) - 8 " What does -4(2) - 8 = ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

-8 - 8
-16?
yes :) Now can you see how that part was BETWEEN the absolute value sign? Absolute value means you always take the POSITIVE of that value inside. So \[\left| -4(2) - 8 \right| = \left| -8-8 \right|= \left| -16 \right| = 16 \]
\[\left| -1-(2)^2 \right| = ? \]
-5
remember, you take the "absolute value" of -5... So \[\left| -1-(2)^2 \right| = \left| -5 \right| = 5 \] And now solve the last part: \[2(2)^3 = ? \]
32
i mean 24
not quite. What does \[2^3 = ? \]
16
err nope.. \[2^3 = 2\times2\times2 = ? \]
8
yes and we wanted: \[2(2)^3 = 2\times2\times2\times2 = ?\]
2(16)
2(2)^3 = 2 times 2 times 2 times 2 = 16
2^3=8
So now we solved the three parts of this equation : \[\left| -4(2) -8 \right| + \left| -1-(2)^2 \right| + 2(2)^3 \] \[= 16 + 5 + 16 = ? \]
37
correcttt
final answer is 37??
yes
thankyou zoo much
you're welcome :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question