## anonymous one year ago MEDAL!! ALGEBRA 2 19. l-4b-8l+l-1-b^2l +2b^3;b=2

1. butterflydreamer

$\left| -4(2) - 8 \right| + \left| -1-(2)^2 \right| + 2(2)^3$

2. butterflydreamer

You are basically solving the above ^ Since they've told you that " b = 2" , this means that you just sub (plug) in 2 where the "b" is. Basically REPLACE all the "b's" with 2 and solve :) BUT you want to take note of the absolute value sign also...

3. butterflydreamer

So firstly, let's simplify the parts inside the first absolute sign " -4(2) - 8 " What does -4(2) - 8 = ?

4. anonymous

-8 - 8

5. anonymous

-16?

6. butterflydreamer

yes :) Now can you see how that part was BETWEEN the absolute value sign? Absolute value means you always take the POSITIVE of that value inside. So $\left| -4(2) - 8 \right| = \left| -8-8 \right|= \left| -16 \right| = 16$

7. butterflydreamer

$\left| -1-(2)^2 \right| = ?$

8. anonymous

-5

9. butterflydreamer

remember, you take the "absolute value" of -5... So $\left| -1-(2)^2 \right| = \left| -5 \right| = 5$ And now solve the last part: $2(2)^3 = ?$

10. anonymous

32

11. anonymous

i mean 24

12. butterflydreamer

not quite. What does $2^3 = ?$

13. anonymous

16

14. butterflydreamer

err nope.. $2^3 = 2\times2\times2 = ?$

15. anonymous

8

16. butterflydreamer

yes and we wanted: $2(2)^3 = 2\times2\times2\times2 = ?$

17. anonymous

2(16)

18. butterflydreamer

2(2)^3 = 2 times 2 times 2 times 2 = 16

19. anonymous

2^3=8

20. butterflydreamer

So now we solved the three parts of this equation : $\left| -4(2) -8 \right| + \left| -1-(2)^2 \right| + 2(2)^3$ $= 16 + 5 + 16 = ?$

21. anonymous

37

22. butterflydreamer

correcttt

23. anonymous

24. butterflydreamer

yes

25. anonymous

thankyou zoo much

26. butterflydreamer

you're welcome :)