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anonymous
 one year ago
Derive the equation of the parabola with a focus at (−2, 4) and a directrix of y = 6. Put the equation in standard form.
f(x) = one fourthx2 − x + 4
f(x) = −one fourthx2 − x + 4
f(x) = one fourthx2 − x + 5
f(x) = −one fourthx2 − x + 5
anonymous
 one year ago
Derive the equation of the parabola with a focus at (−2, 4) and a directrix of y = 6. Put the equation in standard form. f(x) = one fourthx2 − x + 4 f(x) = −one fourthx2 − x + 4 f(x) = one fourthx2 − x + 5 f(x) = −one fourthx2 − x + 5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when focus and directrix are given use the deinition of the parabola or locus method.. let (x,y) be the point on the reqd parabola then distance of (x,y) from (2,4) is sqrt ( (x+2)^2+(y4)^2 ) and distance of (x,y) from y=6 is (y6) units so by definition of parabola we have sqrt ( (x+2)^2+(y4)^2 ) = (y6) squaring both sides we have (x+2)^2+(y4)^2 =(y6)^2 and now just simplify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay :) Can you help with one more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Derive the equation of the parabola with a focus at (0, 4) and a directrix of y = 4. (x  x)^2 + (y  4)^2 = (x  0)^2 + (y  4)^2 y^2 8y + 16 = x^2 + y^2 + 8y + 16 16 y = x^2 y =  x^2 / 16 (or (1/16)x^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what do u think it is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0correct haha, thank you you are a lifesaver!!! :)
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