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anonymous

  • one year ago

y-k=a(x-h)2,a=1,h<0,k>0, in which quardrant is the vertex?

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  1. misssunshinexxoxo
    • one year ago
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    This might help; http://openstudy.com/study#/updates/4f6aa0cee4b014cf77c7d01f

  2. campbell_st
    • one year ago
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    rewriting the equation into vertex form you get \[y = a(x - h)^2 + k\] the vertex is at (h, k) is h < 0 this is the x value... so it it left of the origin k > 0 this is the y have in the vertex so this is above the origin so you need to locate a point left of the origin and above the origin so which quadrant is that..?

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