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anonymous
 one year ago
taking the square root and show steps
4x^2+8x+3=0
anonymous
 one year ago
taking the square root and show steps 4x^2+8x+3=0

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1sounds like you want to complete the square on one side to solve

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[4x^2+8x=3 \\ \text{ divide both sides by 4 } \\ x^2+2x=\frac{3}{4}\] do you recall how to factor x^2+2x+1?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1hint: \[x^2+2x+1=(x+1)^2 \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1add one on both sides and try to use that last equation I posted

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04x^2 + 8x + 4 = 1 (2x+2)^2 = 1 2x+2 = plus or minus 1 x = 1/2 or 3/2 ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1seems great! \[x^2+2x=\frac{3}{4} \\ x^2+2x+1=\frac{3}{4}+1 \\ x^2+2x+1=\frac{3}{4}+\frac{4}{4} \\ (x+1)^2=\frac{1}{4} \\ x+1= \pm \frac{1}{2} \\ x= 1 \pm \frac{1}{2} =\frac{2}{2} \pm \frac{1}{2}=\frac{2 \pm 1}{2} \\ \text{ so } x=\frac{2+1}{2}=\frac{1}{2} \text{ or } x=\frac{21}{2}=\frac{3}{2}\] your way looks cute too :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you could you help me with completing the square on the same question?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1on the same question you already did that

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you wrote 4x^2+8x+4 as (2x+2)^2 (2x+2)^2 is the square of (2x+2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so taking the square and compting the square is the sam eequation?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I think I'm not sure what you are asking? you solved the equation above by completing the square.. then you took square root of both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so im suppose to show my work for completing the square and taking the root but in that i did both right?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[(2x+2)^2 =1 \text{ this is what you got after completing the square } \\ \text{ then you took square root of both sides } \\ \sqrt{(2x+2)^2}=\sqrt{1} \\ \sqrt{(2x+2)^2}=1 \ \text{ but this means } 2x+2=\pm 1 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so thats the answer for completing the square ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1that is the answer by using the completing the square method

freckles
 one year ago
Best ResponseYou've already chosen the best response.1that is the answer you would also get by using any method there is to solve a quadratic such as the quadratic formula or factoring

freckles
 one year ago
Best ResponseYou've already chosen the best response.1though it would be a bit tricky to factor the expression on the left hand side since it wouldn't be doable over integers but that doesn't mean it can't be done at all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could i give that whole equation and answer all the questions in one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0welll besides the factoring

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I don't see how taking the square root and completing the square should have there on separate method you complete the square then take square root but anyways quadratic formula is easy you just use: \[x=\frac{b \pm \sqrt{b^24ac}}{2a}\] factoring 4x^2+8x+3 is actually not tricky (I lied ) 4(3)=6(2) and 6+2=8

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[4x^2+8x+3 = 4x^2+6x+2x+3 \text{ factor this by grouping }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ur confusing me with all this

freckles
 one year ago
Best ResponseYou've already chosen the best response.1but in either method you use you should get the solutions: x=1/2 or x=3/2

freckles
 one year ago
Best ResponseYou've already chosen the best response.1with the use of quadratic formula or factoring?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0both. ur talking about factoring rn or

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I was talking about both quadratic formula and factoring above:

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[ax^2+bx+c=0 \text{ gives } x=\frac{b \pm \sqrt{b^24ac}}{2a} \text{ is quadratic formula }\] you never seen this formula before?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i have but im not sure how it works

freckles
 one year ago
Best ResponseYou've already chosen the best response.1can you compare: ax^2+bx+c=0 to 4x^2+8x+3=0 and identify a,b, and c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my math program is super confusing and dosnt explain why it is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i just need to answer these question

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435044171838:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435044201581:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.1comparing your equation to that equation tells us what a,b, and c are

freckles
 one year ago
Best ResponseYou've already chosen the best response.1now you try pluggin into the formula I gave to find the solution we call x

freckles
 one year ago
Best ResponseYou've already chosen the best response.1the solutions shouldn't differ from the solutions you got previously

freckles
 one year ago
Best ResponseYou've already chosen the best response.1just the method to get the answer is a bit different

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeh i've noticed when i use mathway

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so 4x^2 + 8x + 4 = 1 (2x+2)^2 = 1 2x+2 = plus or minus 1 x = 1/2 or 3/2 is staking the square root and completing the square is (2x+2)^2 \[\sqrt{(2x+2})^2=\sqrt{1}\] one right sorry this isnt making ant sense

freckles
 one year ago
Best ResponseYou've already chosen the best response.1In the completing the square method which you are already done, yes you do take the square root of both sides to solve once you got it in the form (mx+n)^2=d .

freckles
 one year ago
Best ResponseYou've already chosen the best response.1have you done the factoring and quadratic formula method yet?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I gave you a start on both earlier .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok is this correct for the quadratic 4x^2 6x2x +3 = 0. 2x(x3)  1(2x 3) = 0 (2x 1) (2x 3) = 0 2x 1 = 0 2x  3 = 0 2x = 1 2x = 3 x = 1/2 x = 3/2 ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.16x2x isn't 8x I think you meant to replace 8x with 6x+2x 4x^2+6x+2x+3=0 now try to factor the left hand side and no you didn't use the quadratic formula the quadratic formula is as I gave it above which was: \[x=\frac{b \pm \sqrt{b^24ac}}{2a}\]
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