anonymous
  • anonymous
6 13 38 ? 532 2675
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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dan815
  • dan815
|dw:1435053690269:dw|
dan815
  • dan815
|dw:1435054001940:dw|
dan815
  • dan815
kind of like a brute force method

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More answers

dan815
  • dan815
|dw:1435054432140:dw|
dan815
  • dan815
or u can write out the diferences and see if you can find a solution to x, such that all the differences are equal, and if the that solves the terms u want
ganeshie8
  • ganeshie8
does this recurrence relation work\[a_0 = 6,\\~\\a_{n}=(a_{n-1}+8-n)*n\]
dan815
  • dan815
ya that works -.- how did u see that
dan815
  • dan815
wait no it doesnt
dan815
  • dan815
thaat works though
welshfella
  • welshfella
no it doesen't
dan815
  • dan815
u prolly typoed but.. how did u find it?
ganeshie8
  • ganeshie8
oh which term is it failing ?
dan815
  • dan815
the brackets were wrong thats all
welshfella
  • welshfella
is it correct for second term?
dan815
  • dan815
oh wait no its fine actually nothing is wrong
welshfella
  • welshfella
6 + (8-2)*2
dan815
  • dan815
|dw:1435055099574:dw|
ganeshie8
  • ganeshie8
Ahh that looks much better than the recurrence relation @welshfella index starts with 0 :)
welshfella
  • welshfella
oh - right - i see
ganeshie8
  • ganeshie8
|dw:1435055237602:dw|
dan815
  • dan815
right
dan815
  • dan815
is ther closed form for this recurrence
ganeshie8
  • ganeshie8
yes but you don't wanto see it
ganeshie8
  • ganeshie8
\[a(n) = -e n^2 \Gamma(n, 1)+6 \Gamma(n+1)+7 e n \Gamma(n, 1)+e n \Gamma(n+1, 1)-e \Gamma(n+1, 1)+1 \]
ganeshie8
  • ganeshie8
http://www.wolframalpha.com/input/?i=solve+a%280%29%3D6%2C+a%28n%29%3D%28a%28n-1%29%2B8-n%29*n
dan815
  • dan815
haha whaat
welshfella
  • welshfella
wow!

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