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mathmath333

  • one year ago

functions

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{Find the minimum value of the function}\hspace{.33em}\\~\\ & f(x)=\log_{2} (x^2-2x+5) \hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    IDK

  3. anonymous
    • one year ago
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    make roots of the equation then use both roots to find the answer

  4. misty1212
    • one year ago
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    unlikely since you cannot take the log of zero

  5. misty1212
    • one year ago
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    find the minimum value of the quadratic

  6. mathmath333
    • one year ago
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    roots are imaginary here

  7. misty1212
    • one year ago
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    which will be the second coordinate of the vertex

  8. misty1212
    • one year ago
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    vertex of \[x^2-2x+5\] should be easy enough to find

  9. misty1212
    • one year ago
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    since log is an increasing function, once you find the minimum value of the quadratic, that will give you the input that produces the minimum value of the log

  10. mathmath333
    • one year ago
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    minimum is 5

  11. misty1212
    • one year ago
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    no it is not

  12. misty1212
    • one year ago
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    the second coordinate of the vertex is not 5, the constant is 5

  13. mathmath333
    • one year ago
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    i put x=0 here x^2-2x+5

  14. misty1212
    • one year ago
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    yeah sure, if you put in 0 you get 5, but the vertex is NOT \((0,5)\)

  15. misty1212
    • one year ago
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    use \[-\frac{b}{2a}\] to find the first coordinate of the vertex

  16. ganeshie8
    • one year ago
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    whats the minimum value of \(x^2 - 10000000x + 1\) ?

  17. misty1212
    • one year ago
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    plug that in to find the second coordinate ( it is definitely not 5)

  18. anonymous
    • one year ago
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    yes

  19. anonymous
    • one year ago
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    misty its girl like u that i study maths u are eaiutiful

  20. misty1212
    • one year ago
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    thank you darling, you look pretty cute yourself

  21. ganeshie8
    • one year ago
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    i should change my profile pic

  22. mathmath333
    • one year ago
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    oh i remember that dy/dx=0, minimum is 4

  23. misty1212
    • one year ago
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    lol pick a cute girl, everyone will love you

  24. anonymous
    • one year ago
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    btw can u explain it with solutionj plz

  25. misty1212
    • one year ago
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    yeah min is 4 and \[\log_2(4)\] is your answer

  26. anonymous
    • one year ago
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    wait let me search cute girl pics damn those are some fine kittens

  27. misty1212
    • one year ago
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    you certainly don't need to use calc to find the vertex of a quadratic though...

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