solve for n P(n,3) = 60

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

solve for n P(n,3) = 60

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I'm assuming the P means Permutations.. do you know the formula?
yes
P(n,r) = n!/(n-r)!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

So I'm assuming they want us to work backwards.. \(\large P(n, r ) = 60 = \frac{n!}{(n-3)!}\) And we know that that \(n> 3 \)
yeah, for sure :)
I don't think they'd make the problem too difficult.. so I'd suggest just plugging in values for n that are greater than 3. So if we try 4; 4! would equal 24, which is too small and not equal to 60. So 4 won't work. Now trying 5: \(\large P(5, 3) = \frac{5!}{(5-3)!} = \frac{120}{2!}\) And what's 120/2?
how to solve this then? i'm required to show a solution
\[0=n ^{3}-3n ^{2}+2n-60\]
i have went all until this equation, and i'm stuck
but 5's gonna work for that equation for sure
I'm not sure if they want you to go into it that deep, I think just plugging in values would suffice
yeah they do! and it's HORRIBLE
but thanks anyway :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question