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anonymous
 one year ago
solve for n P(n,3) = 60
anonymous
 one year ago
solve for n P(n,3) = 60

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Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0I'm assuming the P means Permutations.. do you know the formula?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0So I'm assuming they want us to work backwards.. \(\large P(n, r ) = 60 = \frac{n!}{(n3)!}\) And we know that that \(n> 3 \)

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0I don't think they'd make the problem too difficult.. so I'd suggest just plugging in values for n that are greater than 3. So if we try 4; 4! would equal 24, which is too small and not equal to 60. So 4 won't work. Now trying 5: \(\large P(5, 3) = \frac{5!}{(53)!} = \frac{120}{2!}\) And what's 120/2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how to solve this then? i'm required to show a solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[0=n ^{3}3n ^{2}+2n60\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have went all until this equation, and i'm stuck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but 5's gonna work for that equation for sure

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure if they want you to go into it that deep, I think just plugging in values would suffice

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah they do! and it's HORRIBLE

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but thanks anyway :)
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