anonymous
  • anonymous
solve for n P(n,3) = 60
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Luigi0210
  • Luigi0210
I'm assuming the P means Permutations.. do you know the formula?
anonymous
  • anonymous
yes
anonymous
  • anonymous
P(n,r) = n!/(n-r)!

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Luigi0210
  • Luigi0210
So I'm assuming they want us to work backwards.. \(\large P(n, r ) = 60 = \frac{n!}{(n-3)!}\) And we know that that \(n> 3 \)
anonymous
  • anonymous
yeah, for sure :)
Luigi0210
  • Luigi0210
I don't think they'd make the problem too difficult.. so I'd suggest just plugging in values for n that are greater than 3. So if we try 4; 4! would equal 24, which is too small and not equal to 60. So 4 won't work. Now trying 5: \(\large P(5, 3) = \frac{5!}{(5-3)!} = \frac{120}{2!}\) And what's 120/2?
anonymous
  • anonymous
how to solve this then? i'm required to show a solution
anonymous
  • anonymous
\[0=n ^{3}-3n ^{2}+2n-60\]
anonymous
  • anonymous
i have went all until this equation, and i'm stuck
anonymous
  • anonymous
but 5's gonna work for that equation for sure
Luigi0210
  • Luigi0210
I'm not sure if they want you to go into it that deep, I think just plugging in values would suffice
anonymous
  • anonymous
yeah they do! and it's HORRIBLE
anonymous
  • anonymous
but thanks anyway :)

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