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anonymous

  • one year ago

Solve the following system. x 2 + y 2 = 25 2x + y = 10 The solution set {(________,__________,_________,________)}

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  1. anonymous
    • one year ago
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    i need 4 answers!!!

  2. anonymous
    • one year ago
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    but how would you do that i only got 2

  3. welshfella
    • one year ago
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    use the substitution method from the second equation y = 10 - 2x Now replace y in the first equation by 10-2x to get an equation in x only solve this for x ( there will be 2 values of x)

  4. anonymous
    • one year ago
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    this is what i got 2x+y=10;2x+2y=25 Step: Solve 2x+y=10 for y: 2x+y+−2x=10+−2x(Add -2x to both sides) y=−2x+10 Step: Substitute (−2x+10) for y in 2x+2y=25: 2x+2y=25 2x+2(−2x+10)=25 −2x+20=25(Simplify both sides of the equation) −2x+20+−20=25+−20(Add -20 to both sides) −2x=5 −2x−2=5−2(Divide both sides by -2) x=−52 Step: Substitute (−52) for x in y=−2x+10: y=−2x+10 y=−2(−52)+10 y=15(Simplify both sides of the equation) Answer: y=15 and x=−52

  5. welshfella
    • one year ago
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    you can then find the corresponding values of y by substituting back in equation 2

  6. anonymous
    • one year ago
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    mm

  7. anonymous
    • one year ago
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    so can you solve this for me please and then explain after

  8. anonymous
    • one year ago
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    Im confused

  9. welshfella
    • one year ago
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    do you follow my method?

  10. anonymous
    • one year ago
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    Not really but please can you do it and explain?

  11. welshfella
    • one year ago
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    2x + y = 10 subtract 2x from both sides y = 10 - 2x OK with that?

  12. anonymous
    • one year ago
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    yes i am

  13. welshfella
    • one year ago
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    right x^2 + y^2 = 25 replace the y in the above equation by 10 - 2x:- x^2 + (10- 2x)^2 = 25 x^2 + (10 - 2x)(10 - 2x) = 25 expanding the brackets:- x^2 + 100 -20x-20x + 4x^2 = 25 adding like terms 5x^2 - 40x + 100 = 25 5x^2 - 40x + 75 = 0

  14. anonymous
    • one year ago
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    alright

  15. welshfella
    • one year ago
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    so now we need to solve this quadratic you can make it easier by dividing each term by 5:- giving x^2 -8x + 15 = 0

  16. welshfella
    • one year ago
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    can you solve this? you need to factor first you need 2 numbers whose product is 15 and when added = -8

  17. anonymous
    • one year ago
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    just do it foe me sir i have limited time

  18. welshfella
    • one year ago
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    (x - 3)(x - 5) = 0 x = 3 or 5 now plug x=3 into the second equation 2x + y = 10 and find y then do the same for x = 5 and you have your 4 solutions

  19. anonymous
    • one year ago
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    i dont have a calculator

  20. welshfella
    • one year ago
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    you dont need one to these

  21. anonymous
    • one year ago
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    i got 4,8,10 and 12 is that correct

  22. welshfella
    • one year ago
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    2(3) + y = 10 6 + y = 10 y = ?

  23. anonymous
    • one year ago
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    if not what are they

  24. welshfella
    • one year ago
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    if already got 2 values of x :- 3 and 5 now we need values of y

  25. welshfella
    • one year ago
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    6 + y = 10 y = ? i'm sure you can do that

  26. anonymous
    • one year ago
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    its 4

  27. welshfella
    • one year ago
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    right now plug in x = 5 to find the second value of y

  28. anonymous
    • one year ago
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    0?

  29. welshfella
    • one year ago
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    yes

  30. welshfella
    • one year ago
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    he has the answers now

  31. anonymous
    • one year ago
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    so its 3,5,4,0?

  32. anonymous
    • one year ago
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    lol my fault

  33. welshfella
    • one year ago
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    yes but pair them up ( x,y) (5,0) and (3,4)

  34. anonymous
    • one year ago
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    but i have 4 answer boxes?

  35. welshfella
    • one year ago
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    well enter then as 5 0 3 4

  36. anonymous
    • one year ago
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    look at the flick of the wrist

  37. anonymous
    • one year ago
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    thanks

  38. anonymous
    • one year ago
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    np

  39. welshfella
    • one year ago
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    yw

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