At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
i need 4 answers!!!
but how would you do that i only got 2
use the substitution method from the second equation y = 10 - 2x Now replace y in the first equation by 10-2x to get an equation in x only solve this for x ( there will be 2 values of x)
this is what i got 2x+y=10;2x+2y=25 Step: Solve 2x+y=10 for y: 2x+y+−2x=10+−2x(Add -2x to both sides) y=−2x+10 Step: Substitute (−2x+10) for y in 2x+2y=25: 2x+2y=25 2x+2(−2x+10)=25 −2x+20=25(Simplify both sides of the equation) −2x+20+−20=25+−20(Add -20 to both sides) −2x=5 −2x−2=5−2(Divide both sides by -2) x=−52 Step: Substitute (−52) for x in y=−2x+10: y=−2x+10 y=−2(−52)+10 y=15(Simplify both sides of the equation) Answer: y=15 and x=−52
you can then find the corresponding values of y by substituting back in equation 2
so can you solve this for me please and then explain after
do you follow my method?
Not really but please can you do it and explain?
2x + y = 10 subtract 2x from both sides y = 10 - 2x OK with that?
yes i am
right x^2 + y^2 = 25 replace the y in the above equation by 10 - 2x:- x^2 + (10- 2x)^2 = 25 x^2 + (10 - 2x)(10 - 2x) = 25 expanding the brackets:- x^2 + 100 -20x-20x + 4x^2 = 25 adding like terms 5x^2 - 40x + 100 = 25 5x^2 - 40x + 75 = 0
so now we need to solve this quadratic you can make it easier by dividing each term by 5:- giving x^2 -8x + 15 = 0
can you solve this? you need to factor first you need 2 numbers whose product is 15 and when added = -8
just do it foe me sir i have limited time
(x - 3)(x - 5) = 0 x = 3 or 5 now plug x=3 into the second equation 2x + y = 10 and find y then do the same for x = 5 and you have your 4 solutions
i dont have a calculator
you dont need one to these
i got 4,8,10 and 12 is that correct
2(3) + y = 10 6 + y = 10 y = ?
if not what are they
if already got 2 values of x :- 3 and 5 now we need values of y
6 + y = 10 y = ? i'm sure you can do that
right now plug in x = 5 to find the second value of y
he has the answers now
so its 3,5,4,0?
lol my fault
yes but pair them up ( x,y) (5,0) and (3,4)
but i have 4 answer boxes?
well enter then as 5 0 3 4
look at the flick of the wrist