anonymous
  • anonymous
Solve this quadratic equation using the quadratic formula. x2 + 8x - 5 = 0
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

pooja195
  • pooja195
List your A,B,C values keeping this in mind \[\huge~\rm~ax^2+bx+c=0\]
anonymous
  • anonymous
\[\frac{ -8\pm \sqrt{(8)^{2}-4(1)(5)} }{ 2(1) }\]
jigglypuff314
  • jigglypuff314
don't forget about the minus sign (negative) in front of that 5 :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
thanks
GreenCat
  • GreenCat
Perfect @gizmo25 Now simplify. \[\frac{ -8 \pm \sqrt{64-20} }{ 2 }\]\[\frac{ -8 \pm \sqrt{44} }{ 2 }\]Oops; I was about to solve it all for you. Can you work it out from here? Hint: Pull out what you can from the square root.
jigglypuff314
  • jigglypuff314
@GreenCat note that I just mentioned the negative so it should be a 64 + 20 instead :)
GreenCat
  • GreenCat
oh yes; it is (-5). Sorry.
GreenCat
  • GreenCat
I was working from Gizmo's equation. @gizmo25 Remember to include the negative in "-5" there.
GreenCat
  • GreenCat
\[\frac{ -8 \pm \sqrt{64+20} }{ 2 }\]\[\frac{ -8 \pm \sqrt{84} }{ 2 }\]Here You go.
anonymous
  • anonymous
thanks :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.