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mathmath333
 one year ago
Identifying Graphical function
mathmath333
 one year ago
Identifying Graphical function

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435071288021:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1graph is \(\large \color{black}{\begin{align} &a.) \ f(x)=f(x) \hspace{.33em}\\~\\ &b.) \ f(x)=f(x) \hspace{.33em}\\~\\ &c.) \ \normalsize \text{neither even nor odd function} \hspace{.33em}\\~\\ &d.) \ f(x)\ \normalsize \text{doesn't exist at atleast one point of the domain.} \hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4\(a\) is wrong because the graph is not symmetric about origin \(b\) is wrong because the graph is not symmetric about \(y\) axis

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1but how did u concluded that

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4the graph passes vertical line test, so it is actually a function. so \(d\) is also wrong.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4or are you asking how to conclude it is not symmetric about origin ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i mean how u judged that the function exists at all points ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1and also what is vertical line test

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4lets rephrase that question : how do you know that the graph is a function ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4it is essential to know the difference between a "relation" and a "function"

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4relation is just about anything, for example : the relation showing friends of a student in your class is a relation \[\{\text{(suresh, krishna), (rajesh, mahes), (suresh, rama), }\cdots\}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4A function is also relation in which every input points to exactly one output. Above relation is NOT a function because \(\text{suresh}\) is pointing to two different students \(\text{krishna}\) and \(\text{rama}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1ok i get that relation can have multiple x values for y , but a function cannot

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4yes is below graph a function or just a relation dw:1435073159068:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1rellation but not function

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1cuz we have 2 different y values for same x value

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4that is also called vertical line test, sweep a vertical line from left to right if the graph touches the vertical line at two different places, then the graph is not a function

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1435073363932:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4lets get back to the actual graph, is it passing vertical line test ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1435073452344:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1yes it passes VLT but for negative values of x there is not y values such as this line

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435073568393:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4that means the function is defined only for x > 0

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1so it is undefined for x<0 ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1then it should be option d.)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4x<0 is not part of the domain, so d is wrong.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1ok i get that thanks

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1what about this graph dw:1435074083721:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1is it also option C.)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435074325926:dw what about this graph

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Yes notice that it is symmetric about \(y\) axis dw:1435074436000:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4\[\large f(x) = f(x)\]

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435074719834:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4nope, it is a function check whether it is odd/even

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1but it fails vertical line test at \(x=0\) ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4why ? it is well defined at x = 0 f(0) = 0 right ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1and what about the points dw:1435075038716:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4look at the graph like this : dw:1435075017594:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1but that graph u draw looks different from the original one

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4f(0) = 0 all other points are not part of the graph because the question clearly says f(x) = 0 at x=0

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1so it is odd function

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Yes how did u figure out it is odd ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1because it is symmetrical with respect to origin

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1is the reason correct

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Yep! dw:1435075546512:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435075812493:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4does it pass vertical line test ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1no it should be option d.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435075996061:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1this is option c.)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4does it pass vertical line test ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1435076100827:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1lol no it doesnt pass

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4so that graph does not represent a function

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435076275748:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1this is odd function ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1do i need to check further if equation of the graph is given

dan815
 one year ago
Best ResponseYou've already chosen the best response.0the function can do anything beyond what u dont see so u cant say its undefined at some domain

dan815
 one year ago
Best ResponseYou've already chosen the best response.0what u do know is that its not mirrored across the y axis or x and y axis

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1but this works fine so far (looks odd function) https://www.desmos.com/calculator/zenrcqo1cg

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1435076810329:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1oh i see that is neat trick

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435077093925:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4lets change option d to a more meaningful one : d) not a function. only a relation.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435077115505:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4im not so comfortable with the phrase : "f(x) doesn't exist..."

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435077115505:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1435077393446:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435077588951:dw ok this looks odd function

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435077669264:dw this too is odd function ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435077791382:dw this is which type of function

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1this looks odd for me

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4it is not an odd function \[\large f(x) =\lfloor x\rfloor\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Is below really true ?\[\large \lfloor x\rfloor =\lfloor x\rfloor \] ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1this is greatest integer function ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1435078161945:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large{ \lfloor 2.5\rfloor=2\\ \lfloor 2.5\rfloor=\lfloor 2\rfloor}=2 \) so this looks odd if it is GIF

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435078351737:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4are you sure \(\large \lfloor 2.5\rfloor = 2\) ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1yes the greatest integer function specifies that \(\lfloor x\rfloor\) will be equal to the smallest integer neighbouring to it.dw:1435079336656:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4\(\large \lfloor 2.5\rfloor = 3\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.43 is the smallest neighbor integer for 2.5

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0how do you plot floor and ceiling with goegebra or some other programs

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0i got it you just right floor :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4yes `f(x)=floor(x)` works just fine :)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0it does not let me do f(x)=floor(x)+x for example
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