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How do i figure out the percentage?
convert 52 and 122 to z-scores using the formula z-score = (given value-mean)/standard deviation once you have the z-scores for 52 and 122, you have two options to find the answer one way would be to use a graphing calculator to find normalcdf(z-score for 52,z-score for 122) other method would be to use a z-table to find the decimal values for each z-score, then subtract (decimal value for 122 minus decimal value for 52)
but vocaloid i don't have the given value-mean/sx
the problem gives you the mean and standard deviation, right? mean = 122 standard deviation = 35 z-score for 52: (52-122)/35 z-score for 122 (122-122)/35
Wowow I am super dumb haha did not read the problem :/
well, alternatively you could use the empirical rule if you recognize that 52 is two standard deviations below the mean
Sorry about that
no need to apologize
So i'm looking at -2 and 0 for z scores hmm
And I got .0228 from the z table :D
oh wait how do i find the z-score for each value? i had to use both to find one (-2,0)
well, since -2 and 0 are integers that makes our work a bit easier well, the empirical rule tells us that the percentage is 34%+13.5% http://www.stat119review.com/_/rsrc/1351288349191/more-material/normal-distribution/empirical-rule/solving-empirical-rule-questions/emprulesmart.bmp
but if you wanted to use a z-table, you would find the table value for 0, then the table value for -2, then subtract the two values