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anonymous
 one year ago
It's really easy just i don't understand it.
Question: If the average score is 122 and the standard deviation is 35, what percentage of students scored between 52 and 122?
anonymous
 one year ago
It's really easy just i don't understand it. Question: If the average score is 122 and the standard deviation is 35, what percentage of students scored between 52 and 122?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do i figure out the percentage?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1convert 52 and 122 to zscores using the formula zscore = (given valuemean)/standard deviation once you have the zscores for 52 and 122, you have two options to find the answer one way would be to use a graphing calculator to find normalcdf(zscore for 52,zscore for 122) other method would be to use a ztable to find the decimal values for each zscore, then subtract (decimal value for 122 minus decimal value for 52)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but vocaloid i don't have the given valuemean/sx

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1the problem gives you the mean and standard deviation, right? mean = 122 standard deviation = 35 zscore for 52: (52122)/35 zscore for 122 (122122)/35

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wowow I am super dumb haha did not read the problem :/

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1well, alternatively you could use the empirical rule if you recognize that 52 is two standard deviations below the mean

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435071928611:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So i'm looking at 2 and 0 for z scores hmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And I got .0228 from the z table :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait how do i find the zscore for each value? i had to use both to find one (2,0)

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1well, since 2 and 0 are integers that makes our work a bit easier well, the empirical rule tells us that the percentage is 34%+13.5% http://www.stat119review.com/_/rsrc/1351288349191/morematerial/normaldistribution/empiricalrule/solvingempiricalrulequestions/emprulesmart.bmp

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1but if you wanted to use a ztable, you would find the table value for 0, then the table value for 2, then subtract the two values
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