anonymous
  • anonymous
Two boats start their journey from the same point A and travel along directions AC and AD, as shown below What is the distance, CD, between the boats? 230.9 ft 284.3 ft 115.5 ft 173.2 ft
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
@jigglypuff314 please help :)
jigglypuff314
  • jigglypuff314
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jigglypuff314
  • jigglypuff314
remember these ratios? :)
anonymous
  • anonymous
yeah thats given for a 30 60 90
jigglypuff314
  • jigglypuff314
CD = BD - BC so let's first try to find BC
anonymous
  • anonymous
so BC = BD - CD
jigglypuff314
  • jigglypuff314
mm that was just to point out that to find CD (the answer) we should try finding BC and BD using what we know about triangles :)
jigglypuff314
  • jigglypuff314
200 sqrt(3) ----- = ---------- BC 1
anonymous
  • anonymous
so would you cross multiply...? I hate this chapter I'm sorry
jigglypuff314
  • jigglypuff314
yes! cross multiply it :)
anonymous
  • anonymous
200 = (BC)(sqrt3)
jigglypuff314
  • jigglypuff314
yes, now divide both sides by sqrt(3)
anonymous
  • anonymous
115.47 = BC
jigglypuff314
  • jigglypuff314
that's right! :) now, let's try to find BD
anonymous
  • anonymous
how would i start that
jigglypuff314
  • jigglypuff314
compare the my drawing to the given picture :) the 200 is where the "x" is right? and BD is where the "x sqrt(3)" is
jigglypuff314
  • jigglypuff314
since we are doing proportions, x is 1 so 200 1 ------ = --------- BD sqrt(3)
anonymous
  • anonymous
BD = 346.4
jigglypuff314
  • jigglypuff314
good! now CD = BD - BC so subtract the two numbers we got :)
anonymous
  • anonymous
230.93 thank you!!
jigglypuff314
  • jigglypuff314
Glad I could help :)

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