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anonymous

  • one year ago

Am I on the right path?? Trig equation. \( \cos^2 = sin \) \( 1-sin^2 = sin \) \( -sin^2-sin+1 \)

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  1. welshfella
    • one year ago
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    yes - but there's an error on the last line - watch the signs and where is the '= 0'

  2. anonymous
    • one year ago
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    kk, got ya. Just needed to make sure I was legal by taking cos^2 and transforming it into 1-sin^2 in an equation :-)

  3. anonymous
    • one year ago
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    where is the error?? the -sin^2??

  4. welshfella
    • one year ago
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    Oh - sorry there's no error (silly me!)i -sin^2 x - sin x + 1 = 0 but its easier to solve quadratic equations with a positive term in x^2 so change all signs giving sin^2 x + sin x - 1 = 0

  5. anonymous
    • one year ago
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    Yes, thanks!!!

  6. welshfella
    • one year ago
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    yw

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