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chaylaceyx3
 one year ago
if z=a+bi and z=abi,
solve z+6(z)=7 for z
chaylaceyx3
 one year ago
if z=a+bi and z=abi, solve z+6(z)=7 for z

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: if z= a+ bi, then: z = a  bi

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2furthermore: z6z=5z

chaylaceyx3
 one year ago
Best ResponseYou've already chosen the best response.0sorry its actually the conjugate of z, not z so its abi

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! then your equation can be rewritten as follows: \[\Large z + 6\bar z = a + bi + 6a  6bi = 7a  5bi = 7\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2which is equivalent to these two real equations: \[\Large \left\{ \begin{gathered} 7a = 7 \hfill \\  5b = 0 \hfill \\ \end{gathered} \right.\] please solve that system for a and b

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2that's right! so, what is z=...?

chaylaceyx3
 one year ago
Best ResponseYou've already chosen the best response.0do i just plug these numbers into 7a5bi?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no, you have to plug, those values, for a and b, into z=a+bi

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2what do you get?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2correct! z=1 is the solution of your complex equation

chaylaceyx3
 one year ago
Best ResponseYou've already chosen the best response.0OH ok! Thanks so much!

chaylaceyx3
 one year ago
Best ResponseYou've already chosen the best response.0question, where does the i go? my teacher asked and i wasn't sure
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