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anonymous

  • one year ago

A ray in the emission spectrum has a wavelength of 3.10 x 1014 meters. Given that the speed of light is 2.998 x 108 m/s, what is the frequency of the ray?

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  1. anonymous
    • one year ago
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    i know the equation to work it out but how would i set it up?

  2. rvc
    • one year ago
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    okay what is the equation?

  3. rvc
    • one year ago
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    \[v=n\lambda \]

  4. rvc
    • one year ago
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    v= 2.998 X 10^8 which can be approximated as 3 X 10^8 lambda = 3.10 X 10^14

  5. anonymous
    • one year ago
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    is that the one ?i thought it was velocity of a wave = frequency x wavelength

  6. anonymous
    • one year ago
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    You have to use the given formula: \[f=\frac{ v }{ \lambda }\], where f is frequency, v is speed and lambda is wavelength.

  7. rvc
    • one year ago
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    |dw:1435079711852:dw|

  8. anonymous
    • one year ago
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    oh okay i see now

  9. rvc
    • one year ago
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    you are correct @flight23

  10. rvc
    • one year ago
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    now just re-arrange

  11. anonymous
    • one year ago
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    okay well i did that and i got an answer way off :(

  12. anonymous
    • one year ago
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    @rvc

  13. anonymous
    • one year ago
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    What did you get?

  14. anonymous
    • one year ago
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    1.0340e16 @Hoslos

  15. anonymous
    • one year ago
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    @Hoslos but hey can you help me on this one question its easy but i just wanna double check lol?

  16. anonymous
    • one year ago
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    No problem. Maybe you did not consider that those figures have exponents. Simply plotting the following in your calculator, you get\[f=\frac{ 2.998*10^{8} }{ 3.10*10^{14} }=9.67*10^{-7}Hz\]

  17. anonymous
    • one year ago
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    ohh i probably put something in wrong but thank u so much appreciate it ! @Hoslos

  18. anonymous
    • one year ago
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    Right.

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