anonymous
  • anonymous
Find the exact value by using a half-angle identity. Sin(7pi/8)
Mathematics
schrodinger
  • schrodinger
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LynFran
  • LynFran
ok so the half angle identity for sin is.....\[\sin \frac{ x }{ 2 }=\sqrt{(1-cosx)/2}\] so \[\sqrt{(1-\cos7\pi)/8} \]\[\sqrt{(1/4)}\sqrt{(1-\cos7\pi)/2}\] we end up with \[\frac{ 1 }{ 2 }*\sqrt{(1-(-1))/2}\] \[\frac{ 1 }{ 2 }*\sqrt{(1+1)/2}\] \[\frac{ 1 }{ 2 }*\sqrt{1}\] ok u can finish it from there?
LynFran
  • LynFran
so did u get the answer?
LynFran
  • LynFran
\[\pm \frac{ 1 }{ 2 }\]

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