A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
please help!!
anonymous
 one year ago
please help!!

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0give me a sec. ill give it a shot

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0ok so now you have \(\dfrac{4}{x3}=3\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then the 3's crosss out?

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0no, what u need to do next is to multiply by (x3) on both the left and right hand side of \[\frac{ 4 }{ x3 }=3\] so that the bottom part will cross out.

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0Not really...on the left hand side... \[\frac{ 4 }{ x3 }\times \frac{ x3 }{ x3 }\] what will u get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0once you multiply the (x3) over you end up with 4=(3)(x3), right?

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0@atreyu6s3x6 that is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so wouldnt the right side cancel?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright well then distribute the 3 through the equation and no not yet

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0no, there is nothing to cancel on the right: 4=3(x3) u need to distribute 3 to (x3) and then simplify...

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0almost but it should be 4=3x+9...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes.. so then you simply move the 9 over to the other side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0almost but it will be a n egative

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0no again :( 4=3x+9 9 on both left and right....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you subtract 9 on both sides. so 49=5

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0and then divide by 3 on left n right, u get....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. then divide by 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in which you end up with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the negative does not cancel. so it is 5/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because im getting 5/3 so would it change to positive?

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.05/3 is the correct ans :) good job @chealseaa_grinn

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's what i got before. haha you said it was wrong. xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh my bad lol good job you proved me wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha it's okay. thank you both for explaining. i'm so slow with math. >.<

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0@chealseaa_grinn u doing fine. getting it slow is better than getting it wrong ;)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but yea your correct..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0progress is progress no matter what speed thats all that counts
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.