please help!!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
first subtract 2 - 5

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

give me a sec. ill give it a shot
-3
ok so now you have \(\dfrac{4}{x-3}=-3\)
you get that.
then add 3
so then the 3's crosss out?
no, what u need to do next is to multiply by (x-3) on both the left and right hand side of \[\frac{ 4 }{ x-3 }=-3\] so that the bottom part will cross out.
and you get 4/x
Not really...on the left hand side... \[\frac{ 4 }{ x-3 }\times \frac{ x-3 }{ x-3 }\] what will u get?
once you multiply the (x-3) over you end up with 4=(-3)(x--3), right?
yes.
@atreyu6s3x6 that is correct
so wouldnt the right side cancel?
alright well then distribute the -3 through the equation and no not yet
no, there is nothing to cancel on the right: 4=-3(x-3) u need to distribute -3 to (x-3) and then simplify...
@sdfgsdfgs correct
okay so 4= 3x+9
almost but it should be 4=-3x+9...
yes.. so then you simply move the 9 over to the other side
xo you get -5/3
almost but it will be a n egative
no again :( 4=-3x+9 -9 on both left and right....
negative* sorry
you subtract 9 on both sides. so 4-9=-5
and then divide by -3 on left n right, u get....
yes. then divide by -3
in which you end up with?
5/3?
the negative does not cancel. so it is -5/3
because im getting -5/-3 so would it change to positive?
5/3 is the correct ans :) good job @chealseaa_grinn
that's what i got before. haha you said it was wrong. xD
oh my bad lol good job you proved me wrong
haha it's okay. thank you both for explaining. i'm so slow with math. >.<
@chealseaa_grinn u doing fine. getting it slow is better than getting it wrong ;)
but yea your correct..
progress is progress no matter what speed thats all that counts
metal? lol

Not the answer you are looking for?

Search for more explanations.

Ask your own question