anonymous one year ago WILL GIVE MEDAL Rewrite the radical as a rational exponent

1. anonymous

2. anonymous

@pooja195 @misssunshinexxoxo

3. anonymous

Question 2: Rewrite the rational exponent as a radical by extending the properties of integer exponents.

4. anonymous

{^o^] help?

5. anonymous

@Vocaloid ? @Mumustar78612 do you think you can help here?

6. Vocaloid

|dw:1435090837276:dw| for the first question

7. anonymous

i havent done this yet sorry

8. anonymous

@paki @Vocaloid

9. Vocaloid

and for the second question... |dw:1435091009545:dw|

10. anonymous

That's fine @Mumustar78612 The choices for #1 are: 2 3/7 2 7/3 2^21 2^4

11. anonymous

Thanks @Vocaloid for #1 but I don't understand #2. the choices are on the first question here: http://learn.flvs.net/educator/student/examform.cgi?rwiggans1*pilot*mpos=3&spos=0&slt=pAI8jbiA7OwsY*3939*0029

12. anonymous

@Ziegenbein @robtobey @freckles

13. freckles

|dw:1435091876191:dw| this rule is definitely what you need

14. freckles

$\frac{2^\frac{3}{4}}{2^\frac{1}{2}}=2^{\frac{3}{4}-\frac{1}{2}}$

15. freckles

can you continue from there?

16. anonymous

Im terrible with fractions @freckles

17. freckles

$\frac{a}{b}-\frac{c}{d}=\frac{ad-cb}{bd}$

18. anonymous

2/8 ?

19. freckles

right and 2/8 can be reduced

20. freckles

8=2(4) $\frac{2}{8}=\frac{2(1)}{2(4)}=\frac{\cancel{2}(1)}{\cancel{2}(4)}$

21. freckles

I think I see two problems above.. $\sqrt[a]{x^b}=x^\frac{b}{a} \\ \text{ just use this for the other question }$

22. anonymous

Right. Soooo then it's 2 1/4 right? @freckles

23. freckles

well the answer would be 2^(1/4)

24. freckles

or in pretty form: $2^\frac{1}{4}$

25. anonymous

That's not any of the answers tho

26. anonymous

@freckles

27. freckles

$\frac{2^\frac{3}{4}}{2^\frac{1}{2}}=2^{\frac{3}{4}-\frac{1}{2}}=2^\frac{1}{4}$ this is right

28. freckles

did you want to put the answer in another form?

29. freckles

you could use $\sqrt[a]{x^b}=x^\frac{b}{a}$ tried that

30. anonymous

probably. The choices are in the link ^^^

31. freckles

notice when comparing 2^(1/4) to x^(b/a) x is 2 b is 1 a is 4

32. freckles

so plug those in on the other side of the equality I just wrote

33. anonymous

Oh I see! Thanks lots!

34. anonymous

Wait... That's still not one of the choices.

35. freckles

I think he still working on $\frac{2^\frac{3}{4}}{2^\frac{1}{2}}$ aren't you @TheDragon ?

36. anonymous

@robtobey umm I already did that one

37. anonymous

Yeah I am @freckles

38. freckles

$\frac{2^\frac{3}{4}}{2^\frac{1}{2}}=2^{\frac{3}{4}-\frac{1}{2}}=2^{\frac{3}{4}-\frac{2}{4}}=2^{\frac{1}{4}}=\sqrt[4]{2^1}$ but remember 2^1 is just 2 so you have $\sqrt[4]{2}$

39. anonymous

Hey Can I Have Some Of You Smart People To Help Me With My Question?

40. anonymous

Oh okay thnx again