anonymous
  • anonymous
The point A(-2, 3) is translated using T: (x,y) → (x + 4, y + 2). What is the distance from A to A'? 2 5 2
Mathematics
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anonymous
  • anonymous
The point A(-2, 3) is translated using T: (x,y) → (x + 4, y + 2). What is the distance from A to A'? 2 5 2
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Square root of 6 2 squared 2 5 or 2 squared 5
MrNood
  • MrNood
if you move the point (-2,3) by adding 4 to the x value, and 2 to the y value what is the new point?
anonymous
  • anonymous
2,5 ?

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anonymous
  • anonymous
2 sqaured 5?
MrNood
  • MrNood
(2,5) is the new point (but that does not give th e answer) slow down a little
MrNood
  • MrNood
|dw:1435090282297:dw|
MrNood
  • MrNood
|dw:1435090347709:dw| So what is the length of each of the black lines?
anonymous
  • anonymous
Is the answer 5?
anonymous
  • anonymous
4 and 2? are thouse the lengths
MrNood
  • MrNood
yes - So you can see a right angle triangle: |dw:1435090449711:dw| What is the length of the long side?
anonymous
  • anonymous
do i square 4 and 2 and get 20 when added up?
anonymous
  • anonymous
and 2 squared 5 when simplified
MrNood
  • MrNood
it is \[\sqrt{20} =\sqrt{4*5} = \sqrt{4} * \sqrt{5} = 2\]
anonymous
  • anonymous
Okay, thanks
MrNood
  • MrNood
sorry - last term should be \[2\sqrt{5}\]

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