anonymous
  • anonymous
How many liters of fluorine gas can react with 32.0 grams of sodium metal at standard temperature and pressure? Show all of the work used to find your answer. 2Na + F2 yields 2NaF
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I have: 32 g NaF x \[\frac{ 1 mol NAF }{ 41.98 g NaF}\] x\[\frac{ 1 mol F _{2} }{ 2 mol NaF }\] x \[\frac{ 1 L F _{2} }{ 1 mol F _{2} }\] = .381
anonymous
  • anonymous
Is that correct?
anonymous
  • anonymous
@gabylovesu

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anonymous
  • anonymous
@karatechopper
anonymous
  • anonymous
@mathstudent55
Vocaloid
  • Vocaloid
@FutureVet one small mistake the last step should be 22.4L F2/1 mol F2, because 1 mol of gas at standard temperature and pressure occupies 22.4L
Vocaloid
  • Vocaloid
other than that, everything else looks ok
anonymous
  • anonymous
Thanks I realized that before I Submitted it.

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